To Write a function called voltage that computes the voltages at different junctions in electrical circuit. after writing the program the output is not coming please help

16 vues (au cours des 30 derniers jours)
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
SOL=M\y;
end

Réponses (5)

Ritvij Sahasrabuddhe
Ritvij Sahasrabuddhe le 2 Jan 2021
You have used 'sol' and 'SOL' as function def output, which are considered 2 different variables

PRASANTH R
PRASANTH R le 27 Déc 2020

Anthony
Anthony le 1 Mar 2021
Modifié(e) : DGM le 4 Mar 2023
function sol = voltage(V,R)
M =[R(2)*R(7)+R(1)*R(2)+R(1)*R(7),-R(1)*R(2),0;
-R(3)*R(4)*R(8),R(4)*R(7)*R(8)+R(3)*R(4)*R(8)+R(3)*R(4)*R(7)+R(3)*R(7)*R(8),-R(3)*R(4)*R(7);
0,-R(5)*R(6),R(6)*R(8)+R(5)*R(6)+R(5)*R(8)];
y =V*[R(2)*R(7);R(4)*R(7)*R(8);R(6)*R(8)];
sol=M\y;
end

Tapan Chahar
Tapan Chahar le 15 Mai 2022
Modifié(e) : DGM le 4 Mar 2023
function [X]=voltage(V,R)
% Writing equations about the 3 node points using Kirchoffs Law & rewritting
% them in terms of matrix we get
if R(1)==0||R(3)==0||R(5)==0
% When resistor R1 =0
if R(1)==0
A=[(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(3)+V/R(7));V/R(5)];
XX=A\b;
X=[V;XX];
end
% When resistor R3 =0
if R(3)==0
A=[(1/R(1)+1/R(2)+1/R(7)),0 ; (-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[(V/R(1)+V/R(7));V/R(5)];
XX=A\b;
X=[XX(1);V;XX(2)];
end
% When resistor R5 =0
if R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)) ; (-1/R(7)),(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(1);V/R(3)+V/R(8)];
XX=A\b;
X=[XX;V];
end
% When both resistor R3 & R5 are =0
if R(3)==0&R(5)==0
A=[(1/R(1)+1/R(2)+1/R(7))];
b=[V/R(1)+V/R(7)];
XX=A\b;
X=[XX;V;V];
end
% When both resistor R1 & R3 are =0
if R(1)==0&R(3)==0
A=[(1/R(5)+1/R(6)+1/R(8))];
b=[V/R(5)+V/R(8)];
XX=A\b;
X=[V;V;XX];
end
% When both resistor R1 & R5 are =0
if R(1)==0&R(5)==0
A=[(1/R(3)+1/R(4)+1/R(7)+1/R(8))];
b=[V/R(3)+V/R(7)+V/R(8)];
XX=A\b;
X=[V;XX;V];
end
% When resistor R1, R3 & R5 are =0
if R(1)==0&R(3)==0&R(5)==0
X=[V;V;V];
end
% When resistor R1,R3 & R5 are non zero
else
A=[(1/R(1)+1/R(2)+1/R(7)),(-1/R(7)),0 ; (-1/R(7)),(1/R(3)+1/R(7)+1/R(8)+1/R(4)),(-1/R(8)) ; 0,(-1/R(8)),(1/R(5)+1/R(8)+1/R(6))];
b=[V/R(1);V/R(3);V/R(5)];
X=A\b;
end
end

Tapan Chahar
Tapan Chahar le 15 Mai 2022
function X = voltage(V,R)
A = [ R(2)*R(7) + R(1)*R(2) + R(1)*R(7), -R(1)*R(2), 0;
-R(3)*R(4)*R(8), R(4)*R(7)*R(8) + R(3)*R(4)*R(8) + R(3)*R(4)*R(7) + R(3)*R(7)*R(8), -R(3)*R(4)*R(7);
0, -R(5)*R(6), R(6)*R(8) + R(5)*R(6) + R(5)*R(8) ];
b = V * [R(2)*R(7); R(4)*R(7)*R(8); R(6)*R(8)];
X = A \ b;
end

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