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How can I plot these 3 ode45 functions in 1 graph?

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Carey n'eville
Carey n'eville le 27 Déc 2020
Commenté : Star Strider le 28 Déc 2020
Hello dear friends I have 3 codes which are different from each other with TH values and tspans ( for first TH=10 and tspan=[0 10], for second TH=20 & tspan=[0 20] and for the third one TH=40 & tspan=[0 40]). I need to plot all these 3 functions in one graph. At first step If it is possible, can you show me combining these three in one code and plot in same graph? Could you help me please? Codes are given below in order:
First:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 10];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=10;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
Second:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 20];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=20;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
Third:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 40];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=40;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end

Réponse acceptée

Star Strider
Star Strider le 27 Déc 2020
The lines are not easily distinguishable.
Try this:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
THv = [10 20 40];
for k = 1:numel(THv)
tspan = [0 THv(k)];
[t{k},XS{k}]=ode45(@(t,XS)BSfunction(t,XS,THv(k)), tspan, XS0);
end
figure
LineStl = {'-','-.','--'};
hold on
for k = 1:numel(THv)
semilogy(t{k}, XS{k}, 'LineWidth',1.5, 'DisplayName', ['TH = ',num2str(THv(k))], 'LineStyle',LineStl{k})
end
hold off
grid
% lgdstr = compose('TH = %d', THv);
legend
figure
for k = 1:numel(THv)
subplot(numel(THv), 1, k)
plot(t{k}, XS{k}, 'LineWidth',1.5)
title(compose('TH = %d', THv(k)));
grid
end
function dXSdt=BSfunction(t,XS,TH)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
% TH=10;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
The first figure plots them all on one axes, the second figure plots them each as separate subplots.
  2 commentaires
Carey n'eville
Carey n'eville le 28 Déc 2020
Modifié(e) : Carey n'eville le 28 Déc 2020
Thank you so much!!!!! I guess this is enough for me
Star Strider
Star Strider le 28 Déc 2020
As always, my pleasure!

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