How do i make this code as simple as possible? :(

1 vue (au cours des 30 derniers jours)
Jungwu Kim
Jungwu Kim le 30 Déc 2020
Commenté : Jungwu Kim le 31 Déc 2020
final_0 = 0;
final_1 = final(numel(final_0)+1:(floor(numel(final)*1/10))*1);
final_2 = final(floor(numel(final)*1/10)*1+1:floor(numel(final)*1/10)*2);
final_3 = final(floor(numel(final)*1/10)*2+1:(floor(numel(final)*1/10))*3);
final_4 = final(floor(numel(final)*1/10)*3+1:(floor(numel(final)*1/10))*4);
final_5 = final(floor(numel(final)*1/10)*4+1:(floor(numel(final)*1/10))*5);
final_6 = final(floor(numel(final)*1/10)*5+1:(floor(numel(final)*1/10))*6);
final_7 = final(floor(numel(final)*1/10)*6+1:(floor(numel(final)*1/10))*7);
final_8 = final(floor(numel(final)*1/10)*7+1:(floor(numel(final)*1/10))*8);
final_9 = final(floor(numel(final)*1/10)*8+1:(floor(numel(final)*1/10))*9);
final_10 = final(floor(numel(final)*1/10)*9+1:floor(numel(final)));
I think anyone who has studied a little bit can make it simple, but I'm not
For your information, the class of those codes is char.
The size of one data is so large that you want to split it into 10 pieces.
Please let me know, and if you have time, I would like to know if this code can be expressed in loop. :((((((((

Réponse acceptée

Ameer Hamza
Ameer Hamza le 30 Déc 2020
First, naming variables like final_1, final_2, ... is a bad coding practise: https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval. Always use arrays. In your case, cell arrays are most appropriate.
You can write the code in a single line like this
final = .. % your arrat
final_split = mat2cell(final, 1, numel(final)/10*ones(1,10))
  5 commentaires
Ameer Hamza
Ameer Hamza le 31 Déc 2020
Modifié(e) : Ameer Hamza le 31 Déc 2020
Just use indexing to access each element of the cell array. There is no need to create seperate variables. For example
final_split{1} % access first element
final_split{2} % access second element
..
..
final_split{end} % access last element
Jungwu Kim
Jungwu Kim le 31 Déc 2020
thank you!! god bless you and happy new year~

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 30 Déc 2020
buffer(final, floor(numel(final)/10)).'
Needs the signal processing toolbox.
The final (11th) row will contain 110227 entries only the first two of which will be nonblank. You might want to consider using ceil instead of floor which will get you 10 rows the last of which has 8 padding positions.
  1 commentaire
Jungwu Kim
Jungwu Kim le 31 Déc 2020
Thank you so much every time!!! :)

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