- b+sqrt(b^2-4*a*c) == b-sqrt(b^2-4*a*c) -- which would occur if sqrt(b^2-4*a*c) == 0
- one of the values is nan
- sqrt(b^2-4*a*c) is imaginary but b is real; in that case, the > operator would compare only the real parts, and the real parts would be equal
A complex number in the course of Müller's method
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    Ali Kiral
 le 31 Déc 2020
  
    
    
    
    
    Commenté : Ali Kiral
 le 31 Déc 2020
            Consider the script below. I am trying to find the roots of  by using Müller's method with initial estimations
 by using Müller's method with initial estimations
 by using Müller's method with initial estimations
 by using Müller's method with initial estimations
N=input('Enter the degree of the main polynomial ');
C=input('Enter the constant ');
for k=1:N
a(k)=input('Enter a coefficient ');
end
a=[C,a];
Pol1=flip(a);
u=input('Enter the first estimate ');
v=input('Enter the second estimate ');
w=input('Enter the third estimate ');
z=input('Enter number of iterations ');
for n=1:z
delta0=(polyval(Pol1, v)-polyval(Pol1, u))/(v-u);
delta1=(polyval(Pol1, w)-polyval(Pol1, v))/(w-v);
h0=v-u;
h1=w-v;
a=(delta1-delta0)/(h1+h0);
b=a*h1+delta1;
c=polyval(Pol1,w);
g1=-2*c/(b+sqrt(b^2-4*a*c));   
g2=-2*c/(b-sqrt(b^2-4*a*c));
if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
x(n)=w+d;  
u=v;
v=w;
w=x(n);
end
When I run it, MATLAB returns 'Undefined function or variable 'd'. d is calculated to be a complex number. MATLAB returns d when I run  or
 or  separately, but does not do for the code. Why is that so?
 separately, but does not do for the code. Why is that so?
 or
 or  separately, but does not do for the code. Why is that so?
 separately, but does not do for the code. Why is that so?0 commentaires
Réponse acceptée
  Walter Roberson
      
      
 le 31 Déc 2020
        if b+sqrt(b^2-4*a*c)>b-sqrt(b^2-4*a*c)
d=g1;
end
if b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c)
d=g2;
end
That code will not assign d under a few circumstances:
Note:
b+sqrt(b^2-4*a*c)<b-sqrt(b^2-4*a*c) implies b + sqrt(b^2-4*a*c) - b < b - sqrt(b^2-4*a*c) - b implies sqrt(b^2-4*a*c) < - sqrt(b^2-4*a*c) implies 2*sqrt(b^2-4*a*c) < 0 implies sqrt(b^2-4*a*c) < 0 . However, algebraically, sqrt() is defined as "principle square root", which is positive when the value is positive, and is 1i * sqrt(-(b^2-4*a*c)) when b^2-4*a*c < 0 -- so sqrt(b^2-4*a*c) < 0 cannot happen unless you define an ordering of imaginary values with respect to 0. The MATLAB < operator ignores the imaginary component... but then you would be comparing 0 to 0, which would not be < .
Which is to say that your second test can never succeed, and your first test is always true unless b^2-4*a*c == 0 (a ligitimate test) or b^2-4*a*c < 0 (because the imaginary component is ignored)
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