Problems with Solving inequalities in matlab
Afficher commentaires plus anciens
Hello, I have a question on how to solve
in matlab.
I have tried the following code:
syms x;
f = (sqrt(x+1)-1)/x;
sol = solve(f<(sqrt(2)-1)/2,x);
but I only get the following error:
sol =
Empty sym: 0-by-1
Warning: Unable to find explicit solution. For options, see help.
Is there someone out there who could help?
Réponses (2)
John D'Errico
le 1 Jan 2021
Modifié(e) : John D'Errico
le 1 Jan 2021
That is not an error. It is a warning message, telling you there is a problem with what you have posed to solve.
There is no explicit solution found, because there are infinitely many solutions.
syms x;
f = (sqrt(x+1)-1)/x;
fplot(f,[-5,100])
yline((sqrt(2)-1)/2);
A solution exists for ALL x, such that the curve is less than the horizontal line drawn. That is to say, whenever x strictly exceeds
xmin = solve(f == (sqrt(2)-1)/2)
vpa(xmin)
3 commentaires
Erik Börjesson
le 1 Jan 2021
Matthew Cassini
le 8 Déc 2022
I don't get why it doesn't give the minimum or maximum value that is a solution, as that is normally how you would solve an inequality. If given 2x > 1 and asked to find x you would say x > 1/2, not theres infinitely many solutions.
You get the "cut points" of your inequality if you solve it as an equation as John D'Errico did.
syms x
f = 2*x==1;
solve(f)
Walter Roberson
le 2 Jan 2021
0 votes
solve() is pretty inconsistent as to whether it can handle inequalities. When it succeeds and you do not use returnconditions then it picks a representative solution instead of showing the inequality boundaries. For example if the range of solution was 3 to 15 it might say 9, but if it were -1 to 15 it might say 0
Catégories
En savoir plus sur Mathematics dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
