I need the Coding to solve the simultaneous equations. To find T, tow, TC.
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shunmugam hemalatha
le 1 Jan 2021
Commenté : Walter Roberson
le 4 Jan 2021
lc
clear all
c0=40;
cd=50;
y0=0.09;
h=0.7;
r=5;
u=0.05;
a=260;
b=0.1;
x='((a*h)/2)+((a*r*T)/3)+((a*h*T*((exp(-u*tow))+b))/3+((a*r*(T^2)*(exp(-u*tow))+b))/8)-(c0/(T^2))+((cd*((3*a*y0*(exp(-u*tow)))-2(2*T*a*b*y0*(exp(-u*tow)))-(2*T*a*(b^2))/6)';
y='1-((u*a*h*(T^2)*y0*(exp(-u*tow)))/6)-((u*a*r*(T^3)*y0*(exp(-u*tow)))/24)-(cd*u*T*y0*(exp(-u*tow))*((3*a-a*b*T)/6))';
TC=(c0/T)+(1/T)*(((a*h*(T^2))/2)+((a*r*(T^3))/6)+((((a*(y0*(exp(-u*tow)))+b)/2))*(((h*(T^3))/3)+((r*(T^4))/12))))+((cd/T)*((((T^2)*y0*(exp(-u*tow))*(3*a-a*b*T))-(a*(b^2)*(T^3)))/6))+tow
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Walter Roberson
le 1 Jan 2021
You cannot solve that without fixing your formulas.
syms T tow
c0=40;
cd=50;
y0=0.09;
h=0.7;
r=5;
u=0.05;
a=260;
b=0.1;
A = a; %??? maybe ?
R = r; %??? maybe ?
B = b; %??? maybe ?
x = ((a*h)/2)+((a*r*T)/3)+((a*h*T*((exp(-u*tow))+b))/3+((a*r*(T^2)*(exp(-u*tow))+b))/8)-(c0/(T^2))+((cd*((3*a*y0*(exp(-u*tow)))-2*(2*T*a*b*y0*(exp(-u*tow)))-(2*T*a*(b^2))/6);
12 1 0 12 1 0 12 34 5 43 21 23 4 3 4 5 43 21 0 1 2 10 12 34 5 6 543 4 5 6 543 4 5 43 2
You have two more ( than you have )
y = 1-((u*a*h*(T^2)*y0*(exp(-u*tow)))/6)-((u*a*r*(T^3)*y0*(exp(-u*tow)))/24)-(cd*u*T*y0*(exp(-u*tow))*((3*a-a*b*T)/6));
sol = solve([x,y], [T tow]);
T = sol.T;
tow = sol.tow;
TC = (c0/T)+(1/T)*(((a*h*(T^2))/2)+((a*r*(T^3))/6)+((((a*(y0*(exp(-u*tow)))+b)/2))*(((h*(T^3))/3)+((r*(T^4))/12))))+((cd/T)*((((T^2)*y0*(exp(-u*tow))*(3*a-a*b*T))-(a*(b^2)*(T^3)))/6))+tow;
disp(T)
disp(tow)
disp(TC)
vpa(T)
vpa(tow)
vpa(TC)
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Plus de réponses (1)
shunmugam hemalatha
le 4 Jan 2021
2 commentaires
Walter Roberson
le 4 Jan 2021
Using solve with quoted strings has not been valid for several releases, and has not been a good idea since 2016 (there were some bugs then that forced using quoted strings for certain differential equations... for nearly any purpose other than differential equations, using quoted strings for symbolic expressions has not been a good idea since r2014a.
I posted the version without quoted strings already and you should have built on that.
Walter Roberson
le 4 Jan 2021
Your code here has the same problem as before, that you have more ( than you have )
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