Can you make the output of this graph have multiple colors, like one timing bit is one color and the next one is another color.

h = [1 1 0 1 0 1 0 1];
bitrate = 1;
n = 1000;
T = length(h)/bitrate;
N = n*length(h);
dt = T/N;
t = 0:dt:T;
x = zeros(1,length(t));
lastbit = 1;
for i=1:length(h)
    if h(i)==1
        x((i-1)*n+1:i*n) = -lastbit;
        lastbit = -lastbit;
    else x((i-1)*n+1:i*n) = lastbit;
    end
 end   
    d=plot(t,x);grid on;
    title('Line code POLAR NRZ-I');
    set(d,'LineWidth',2.5);
    axis([0 length(h) -1.5 1.5]);
    counter = 0;
    lastbit = 1;

for i = 1:length(t)
    if t(i)>counter
        counter = counter + 1;
        if x(i)~=lastbit
            result(counter) = 1;
            lastbit = -lastbit;
        else result(counter) = 0;
        end
    end
    
end
disp(result);

Answer 1

[Image Analyst]

To plot in different colors you have to specify a linespec in plot, like

d=plot(t,x, 'r-', 'LineWidth', 2); % Plot red line of width 2.
d=plot(t,x, 'b-', 'LineWidth', 3); % Plot blue line of width 3.
d=plot(t,x, '-', 'LineWidth', 2); % Plot line of width 2 in next default color;

Here's a full demo:

numLines = 10
lineColors = jet(numLines);
x = linspace(0, 2*pi, 1000);
period = pi;
legendStrings = cell(numLines, 1);
for k = 1 : numLines
	y = sin(2*pi*x/(k * period));
	plot(x, y, '-', 'Color', lineColors(k, :), 'LineWidth', 3);
	hold on;
	legendStrings{k} = sprintf('Curve #%d', k);
end
grid on;
xlabel('x', 'FontSize', 20);
ylabel('y', 'FontSize', 20);
legend(legendStrings, 'Location', 'southwest');

Also see attached m-file for a different demo.

[Crish]

That's good but I want that one line to have many different colors when plotted.

[Image Analyst]

Then just plot markers in that color, not lines:

x = linspace(0, 2*pi, 1000);
period = pi;
y = sin(2*pi*x/period);

numMarkers = numel(y)
lineColors = jet(numMarkers);
for k = 1 : length(x)
	plot(x(k), y(k), '.', 'Color', lineColors(k, :), 'MarkerSize', 22);
	hold on;
end
grid on;
xlabel('x', 'FontSize', 20);
ylabel('y', 'FontSize', 20);

[Crish]

Wonderful. Thank you very much!

[Image Analyst]

Crish, here's another demo where I vary teh color with y value instead of x value:

clear all;
close all;
clc;
format long g;
format compact;
fontSize = 15;
fprintf('Beginning to run %s.m ...\n', mfilename);

x = linspace(0, 2*pi, 1000);
period = pi;
y = sin(2*pi*x/period);

numMarkers = numel(y);
markerColors = jet(numMarkers);
subplot(2, 1, 1);
for k = 1 : length(x)
	plot(x(k), y(k), '.', 'Color', markerColors(k, :), 'MarkerSize', 30);
	hold on;
end
grid on;
caption = sprintf('Line Color Varies Along X.  Composed of %d Differently Colored Markers', numMarkers);
title(caption, 'FontSize', 20);
xlabel('x', 'FontSize', 20);
ylabel('y', 'FontSize', 20);
xlim([min(x), max(x)]);
% Maximize the figure window.
g = gcf;
g.WindowState = 'maximized';

% Do it again but instead of changing color as we move along the x axis, 
% change it as we go along the y axis.  So the marker color depends on the y value.
subplot(2, 1, 2);
numMarkers = numel(unique(y));
markerColors = jet(numMarkers);
miny = min(y);
maxy = max(y);
% Get indexes into the color map for each y value.
colorMapRows = round(rescale((y - miny) / (maxy - miny), 1, numMarkers));
for k = 1 : length(x)
	thisMarkerColor = markerColors(colorMapRows(k), :);
	plot(x(k), y(k), '.', 'Color', thisMarkerColor, 'MarkerSize', 30);
	hold on;
end
grid on;
caption = sprintf('Line Color Varies With Y Value.  Composed of %d Differently Colored Markers', numMarkers);
title(caption, 'FontSize', 20);
xlabel('x', 'FontSize', 20);
ylabel('y', 'FontSize', 20);
xlim([min(x), max(x)]);

fprintf('Done running %s.m.\n', mfilename);

I think you pretty much have all possibilities now.

Answer 2

[Crish]

I tried your code but it's not really much working on a square wave. It's not making a vertical line.

[Image Analyst]

Correct. You do not have any data points there. If you really need lines between the data points, you can go to some more trouble to get them by drawing a line from each point to the prior point but the line will be all one color, not have a color gradient. I'm pretty sure you're capable of that but if you're not, attach your data.

Answer 3

[Crish]

It's fine now. I already solved the problem. Thank you for your ideas.