How can I find the nonzero values in an cells array?.

The following code generates an cell array Index [1x29], where each cell is an array [29x6]:

for i = 1 : size(P1_cell,1)
    for j = 1 : size(P1_cell,2)
        [Lia,Lib] = ismember(P1_cell{i,j},PATTERNS_FOR_ERANOS_cell{1},'rows'); 
        Index1(i,j) = Lib  % 29x6
    end
        Index{i} = Index1; % 1x29
end

How can I find the nonzero values in an cells array?, and generate an array with the values from that search. I tried the following loop, but it doesn't work, it creates conflict with the previous one:

for i = 1 : length(Index)
            
    for j = 1 : length(Index)
        Non_ceros = length(find(Index{:,i}(j,:))); %%  I just need the length of the find function output
    end
end

I need help, Thanks in advance.

[dpb]

What result do you want/need? Just the total number of nonzero elements in each Index1 array, or information on number per row/column inside?

[Yro]

Hi, thanks for your answer, I need the number of non-zero values in each row of the Index1 array.

Thanks.

[David Hill]

Look at nnz() function

[Yro]

Thanks, but I need the number of non-zero values in each row, nnz function return the number of the nonzeros values in the full array.

Answer 1

[David Hill]

Non_ceros=zeros(length(Index));
for i = 1 : length(Index)      
    for j = 1 : length(Index)
        Non_ceros(i,j) = nnz(Index{i}(j,:));
    end
end

[Yro]

Thanks,

I tried that but I get the following error:

error: Index(2,_): out of bound 1 (dimensions are 1x6)

I don't know why the dimensions are right.

Thanks a lot

[David Hill]

Works fine for me.

%generates 1x29 Index cell array
for k=1:29
  Index{k}=randi(10,29,6)-1;
end

Non_ceros=zeros(length(Index));
for i = 1 : length(Index)      
    for j = 1 : length(Index)
        Non_ceros(i,j) = nnz(Index{i}(j,:));
    end
end
%Non_ceros is a 29x29 matrix

[Yro]

I found an error in the other part of my code that generated the array,

Thanks for your time.