Réponses (2)

Cris LaPierre
Cris LaPierre le 12 Jan 2021

2 votes

See MATLAB Onramp, in particular Chs 2, 5, 8, 12 & 13.
David Hill
David Hill le 12 Jan 2021

0 votes

If the matrix 'index' indexed at (1,1) equals 1, then assign S1 =0 and S2 = 0.
if index(1,1)==1
S1=0;
S2=1;
end

2 commentaires

Nyam Jargalsaikhan
Nyam Jargalsaikhan le 12 Jan 2021
Modifié(e) : Nyam Jargalsaikhan le 12 Jan 2021
A=[1 5 7 8 4 2 6 3];
[~, index]=sort(A);
if index(1,1)==1
S1=0;
S2=0;
end
if index(1,1)==2
S1=0;
S2=0;
end
if index(1,1)==3
S1=0;
S2=0;
end
what about this one?
David Hill
David Hill le 12 Jan 2021
Matlab has good documentation. You should look at the sort() function.
help sort
You will see that the index array contains the index numbers for rearraigning A to sort it.
A(index)==sort(A);
The code above seems poorly written. First, index is only one dimension, so you only need to index at (1). Second, all if statements do the same thing so combining them into a single statement would be better.
A=[1 5 7 8 4 2 6 3];
[~, index]=sort(A);
if ismember(index(1),[1 2 3])
S1=0;
S2=0;
end

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