Index exceeds matrix dimensions.

2 vues (au cours des 30 derniers jours)
Locks
Locks le 10 Avr 2013
hi,
I have used this code here:
for i=1:length(data8(:,1))
if(data8(i,8)>1.1)
data8(i,:) = [];
end
if(data8(i,8)<0.9)
data8(i,:) = [];
end
end
where data 8 is a matrix with 8 columns, and I get this error message:
Index exceeds matrix dimensions.
Error in construct_data (line 43) if(data8(i,8)>1.1)
has anybody an idea why this can happen?

Réponse acceptée

Cedric
Cedric le 10 Avr 2013
Modifié(e) : Cedric le 10 Avr 2013
length(data8(:,1))
is evaluated only once at the beginning of the FOR loop. It is e.g. 10. Then you remove rows from data8 , whose size therefore decreases (9 rows, 8 rows, ..). At one point the loop index (that is still incremented until it hits 10) becomes larger than the remaining number of rows in data8.
  3 commentaires
Cedric
Cedric le 10 Avr 2013
Modifié(e) : Cedric le 10 Avr 2013
Several ways, one is:
i = 0 ;
while i < size(data8, 1)
i = i + 1 ;
% .. whatever you have to do.
end
Locks
Locks le 10 Avr 2013
great, thanks!

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