Euler's method
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1 commentaire
James Tursa
le 13 Jan 2021
What have you done so far? What specific problems are you having with your code?
Réponses (2)
WalterWhite
le 13 Jan 2021
0 votes
Steve Areola
le 5 Août 2023
0 votes
clc
a=0;b=2;N=10; alph=0.5;
h=(b-a)/N; t(1)=a; w(1)=alph;
f = @(t,y) y-t^2+1;
for i=2:N+1
t(i)=a+(i+1)*h;
w(i)=w(i-1)+h*f(t(i-1),w(i-1));
end
disp("t w")
x=[t;w];
fprintf("%5.9f %5.9f\n",x)
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