how fined vector index

I have a vector of 60,000 x 1, each part containing the values 0-9

What do I need to do to find out in which cells, for example, the value is 1?

The goal is to have an index of cells equal to 1

[Athrey Ranjith Krishnanunni]

myVector = randi([0,9],60e3,1); % vector of 60,000x1 containing integers between 0 and 9
linearIdx = find(myVector == 1); % linear indices of elements equal to 1

You might also want to look at ind2sub if you plan to not just limit to vectors.

Also, most applications support logical indexing, which is faster and uses less memory than linear indexing, so maybe look that up too.

[lech king]

Thank you Thank you very much

[Jan]

@ARK: Please post this as an answer, not as a comment. Then we can vote for it and select it as accepted asnwer.

[Athrey Ranjith Krishnanunni]

@Jan I didn't know whether OP wanted a more complicated solution, so I just suggested this simplified version to see if it'll serve their purpose. I'll put it up as the answer.

Answer 1

[Athrey Ranjith Krishnanunni]

Even though OP says "cells", based on their response to my comment, it seems that they were talking about simple vectors after all. In which case the following code:

myVector = randi([0,9],60e3,1); % vector of 60,000x1 containing integers between 0 and 9
linearIdx = find(myVector == 1); % linear indices of elements equal to 1

will work (in the second line, 1 can be substituted for whatever number is required).

It would be a good idea to look at ind2sub if you plan to also use matrices (instead of just vectors) some day.

Also, most applications support logical indexing, which is faster and uses less memory than linear indexing, so maybe look that up too.

[lech king]

Thank you Thank you very much