evaluate expression

3 vues (au cours des 30 derniers jours)
omnia
omnia le 12 Mai 2011
I have equation y=x*exp( (1-y)/(A*y)*B ) where A nd B constants in my program. I have a vector values for x. How can I evaluate y to plot y versus x ?

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 12 Mai 2011
ezplot(['y-x*exp( (1-y)/(' num2str(A) '*y)*' num2str(B) ')'],[x(1) x(end)])
more
As = ...;
Bs = ...;
y = zeros(size(x));
for j = 1:length(x)
y(j) = fzero(@(y)y-x(j).*exp( (1-y)./(As*y)*Bs ),1);
end
plot(x,y);
  2 commentaires
John D'Errico
John D'Errico le 12 Mai 2011
It is generally not a good idea to convert the numeric values into strings to then pass into ezplot. This loses precision. Far, far better is to use an anonymous function here.
omnia
omnia le 13 Mai 2011
Thank you alot

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Plus de réponses (1)

Andrew Newell
Andrew Newell le 12 Mai 2011
It would be simpler to provide y and solve for x:
y = -1:0.01:1;
x = y.*exp(- (1-y)./(A*y)*B );
In plotting this, you have to be careful because x goes to Inf or -Inf as y approaches zero from below:
I = y < 0 & abs(x) < 10;
plot(x(I),y(I))
hold on
I = y > 0 & abs(x) < 10;
plot(x(I),y(I))
  1 commentaire
omnia
omnia le 13 Mai 2011
yes I know it is easier to provide y and solve for x, but I don't have y. The input to my file is x values.

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