Can't use laplace transformed expression with transfer function.
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
When i laplace transform my expression ('r2') it becomes "sym" and i cant use it with any system or transfer function in the 's'-domain.
('r1') is numerically equivalent, but declared manually. it works fine.
Is there a way to make Laplace transforms become "tf"?
0 commentaires
Réponse acceptée
Rohit Pappu
le 29 Jan 2021
A plausible solution is as follows
% Collect the coefficients of r2
h = collect(r2);
% Split the coefficients into numerator and denominator
[ii,jj] = numden(h);
% Convert the coefficients into numerical values
num = sym2poly(ii);
den = sym2poly(jj);
% Generate Transfer function from the above coefficients
model= tf(num,den);
2 commentaires
Walter Roberson
le 29 Jan 2021
There can be additional work needed if there is a delay on the system. That shows up as an exp() term symbolically.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Calculus dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!