divide the matrix to blocks

I need to divide matrix to blocks have size (1*3) how can write (for loop) to get blocks as the following example

matrix = [1 4 3 5 7 1;4 2 1 5 4 7;8 0 1 4 5 6] I need first block = [1 4 3] second block = [5 7 1] third block = [4 2 1]

and so on

[Cedric]

What have you tried so far?

Answer 1

[Matt J]

This file might be useful

http://www.mathworks.com/matlabcentral/fileexchange/35085-split-nd-array-into-equal-sized-cells

[Matt J]

In your case, it would apply as follows,

 result=mat2tiles(yourMatrix,[1,3]);

[Aseel H]

it is OK, but how i can deal with the values of each cell

by meanning, I need to make some operation on the first values of all cells as multiple it by constant as 4 i.e the first cell will become = 4,4,3 the second cell will become = 20,7,1 and so on

[Matt J]

It was never necessary to split the matrix into blocks, for that. All you needed to do was

 matrix(:,1:3:end) = 4*matrix(:,1:3:end);

For more complicated things, you can use the CELLFUN command, or BLOCKPROC.

[Aseel H]

No, I can not use matrix(:,1:3:end) = 4*matrix(:,1:3:end); because I need deal with values of each block alone,for example

X = [5 6 4 7 9 8;5 0 1 4 7 3];

after that: cell1 = [5,6,4] cell2 = [7,9,8] and do on

After that will be execute some operations on the values of each individual cell, according to some conditions if they apply to the three values in each cell or not

In other words how I call on the values of each cell

The first value of cell one the second value of cell one ......... etc

[Matt J]

You need to read about cell arrays, in particular

http://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

Answer 2

[Aseel H]

Deleted by Matt J