How to reduce the matrix
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Sir,
I have a matrix of size 830x27,want to reduce the size to some ax27 using processpca?how to reduce it?
4 commentaires
Hi.
a=rand(830,27);
n=10;
for i = 1:floor(size(a,1)/n)
eval(['a' num2str(i) ' = a(n*(i-1)+1:n*(i-1)+10,:)'])
end
Minnu
le 2 Mai 2013
Zhang lu
le 2 Mai 2013
a=rand(830,27);
n=30;
for i = 1:floor(size(a,1)/n)
eval(['a' num2str(i) ' = a(n*(i-1)+1:n*i,:)'])
end
if mod(size(a,1),n)~=0
I=floor(size(a,1)/n)+1;
eval(['a' num2str(I) ' = a(n*i+1:end,:)'])
end
No, Zhang, do not do this. Using EVAL to hide an index in the name of a varibale is a really bad idea. This reduces the processing speed substantially, impedes debugging and required equivalently obtuse methods to access the variables later. It would be tremendously smarter to use an index as index (!):
a{I} = a(n*i+1:end, :)
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