Lets assume that I have a matrix A 300x2 with x y coordinates. I want to find how many times a specific [x y] exists in this matrix A. I ve tried this but find can search only single values.
i = find(A == [x y]);
Any idea?????

1 commentaire

Azzi Abdelmalek
Azzi Abdelmalek le 19 Fév 2014
[Kris zenitis commented]
Yeah thank you man!!

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 Réponse acceptée

Jan
Jan le 14 Mai 2011

7 votes

Another method:
I = sum(A(:, 1) == x & A(:, 2) == y);
EDITED: Buggy multiplication method removed. Thanks Andrei!
This method is about 50 times faster than ISMEMBER(A, b, 'rows').

3 commentaires

Andrei Bobrov
Andrei Bobrov le 14 Mai 2011
Hi Jan! may be it?
I = sum((A(:, 1) == x).* (A(:, 2) ==y));
Jan
Jan le 14 Mai 2011
@Andrei: You are right. But the multiplication is slower than the AND operator. Therefore I've removed this method.
Esubalew
Esubalew le 25 Juil 2017
Hi Jan,
The method you suggested above is a good one, but incase if A is 1000 by 100 matrix or a bigger matrix, it there a better way to cind the row of A, A_i such that A_i ==v for some vector v of size =size(A,2)?
Thank you!

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Plus de réponses (1)

Matt Fig
Matt Fig le 14 Mai 2011

1 vote

For example:
A = reshape(1:12,6,2) % A sample matrix for demonstration...
I = ismember(A,[4 10],'rows');
If you want to find how many there are, use:
S = sum(I)

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