Matrix subtraction every two adjacent column

Hello everyone,I have a matrix x with MxN = (3750X666) and I want to subtract every two adjacent column,normalize it and create a new matrix y= [x(:,n)-x(:,1:n-1))] ./ x(;,n), n start with 2nd column and end with N, how can I do it?

[Matt J]

We covered this, I believe, in your almost identical question here,

https://www.mathworks.com/matlabcentral/answers/743387-how-to-substract-every-two-adjacent-column-from-a-matrix?s_tid=srchtitle

[MUHAMMAD SYAKIR YUSRI]

Yes its the same question, but it doens't perform the subtraction throughout the whole length (666). I need it to perform the subraction of the every two adjacent column and normalize it for the whole length.

[Matt J]

Here is the solution you were given. As you can see, it does 664 subtractions, which is exactly the number of pairs available (separated by a stride of 2) along the whole width of your matrix.

x=rand(3750,666);
y=(x(:,3:end)-x(:,1:end-2))./x(:,2:end-1);

whos y

  Name         Size                Bytes  Class     Attributes

  y         3750x664            19920000  double              

[MUHAMMAD SYAKIR YUSRI]

Thank Matt, i was confused earlier. Thank you for the explanation.

Answer 1

[Stephan]

% sample data
A = randi(10,5,3)

% second col minus first and so on
B = A(:,2:end) - A(:,1:end-1)

% first col minus second and so on
C = A(:,1:end-1) - A(:,2:end)

Answer 2

[Matt J]

y=diff(x,1,2);