Creating sub-vectors with equal entries

Hi all, for a homework assignment I'm given an arbitrary array that contains 1's and 0's. (numeric array not logical). I'm not allowed to use the find fuction. I'm supposed to return a vector with number of consecutive zeros, so for:

x = [0 1 0 0 0 1 0 1 1 1 0 0 0 1 0 1 1 0 0];

we would get the output y = [1 3 1 3 1 2].

What I want to know is if I could split x into subvectors for every zero, If I change the matrix x to x1 by x1 = +(~x). then I can take the sums of the individual subvectors and put them into an array giving me the output vector I want. here's a more visible example:

Given: x = [0 1 0 0 0 1 0 1 1 1 0 0 0 1 0 1 1 0 0];

Step 1, Invert x; x1 = +(~x)

x1 = [1 0 1 1 1 0 1 0 0 0 1 1 1 0 1 0 0 1 1];

Step 2, Break up vector x1 into subvectors

[1 0]

[1 1 1 0]

[1 0]

[0]

[0]

[1 1 1 0]

[1 0]

[0]

[1 1]

Step 3, sum all of the subvectors

1

3

1

0

0

3

1

0

2

Step 4, eliminate the zeros and reshape into vector

[1 3 1 3 1 2]

Any and all help appreciated. Thanks

Answer 1

[darova]

Use for loop

x = ~x;
j = 0;
k = 0;
n = sum(diff(~x));       % number of series '0'
ix = zeros(ix,1);
for i = 1:length(x)-1
    j = j + 1;
    if x(i)==0 && x(i+1)==1
        k = k + 1;        
        ix(k) = j;
        j = 0;      
    end
end