Write matrix or array without overwriting

Hi,

I am getting a parameter called 'test' in a for loop. I want to write it to a matrix or array without overwriting. Each loop has a different dimension so that makes it a bit complicated.

I need on line h 'r' values of test, line h the new 'r' values of test and so on. So test needs to come in row h, column r.

for h = 3:10
   ...
 ...
...
A = []

for r = 1:g
...
    for m = 1:numbcenterlines
... 
     percentage(m) = sum(distance>0 & distance <1) / numel(distance)*100;
     test = max(percentage,[],'all');
    end

    A(r,h) = [A;test] %this part doesn't work well so my question is how to fix this part and get an array here with all the test values without overwriting
end 
end

Answer 1

[Stephen23]

You are mixing up two different approaches to adding data in a loop: concatenation and indexing. Just pick one, e.g.:

A = [A;test];

[Dion Theunissen]

Thanks, on this way it is overwriting cause each 'h' needs a different row. now it takes the same column.

I need to add the 'test' in row h column r.

[Walter Roberson]

A(r,h) = test;

[Dion Theunissen]

On this way it doesnt add it to the existing matrix. when it turns in the second loop it fills zeros on the earlier columns

[Walter Roberson]

I do not understand what you want.

Maybe something like

A = {};

and later

A(r,h){end+1} = test;

???

[Dion Theunissen]

A =

         0         0   67.9666
         0         0   57.2263
         0         0   73.3220
         0         0   19.6101
         0         0   21.3058
         0         0   88.3791
         0         0   78.7196
         
 A =

         0         0         0   36.5854
         0         0         0   36.5854
         0         0         0   36.5854
         0         0         0   36.5854
         0         0         0   36.5854
         0         0         0   36.5854
         0         0         0   36.5854

This is the result, but i want to save the third column aswell.

[Walter Roberson]

Do not do the

A = [];

inside your outer loop.