How to load all the data in one folder
Afficher commentaires plus anciens
Path = 'D:\50-350\';
File = dir( fullfile(Path,'*.dat'));
FileNames = {File.name}';
Length_Names = size(FileNames,1);
for i=1:Length_Names
filename=strcat(Path, FileNames(i));
eval(['Data',num2str(i),'=','load(filename{1,1})',';']);
end
I have 3 targets here:
1、Find out all the files with '.dat' in folder '50-350';
2、Read the data;
2、Rename the data from ‘Data1 Data2 Data3 Data4...’ one by one;
By the codes above, I successfuly achieve the goals, but I find that the size of the data change.
For example: I load the ' 31.dat ' by the above codes, and rename it as ' Data31'. The size of Data31 is 3353×10 . If I read '31.dat' directly, the size is 2501×10. I am wonder why it happened.
2 commentaires
Sikai Wu
le 19 Fév 2021
For robustness you should preallocate Data before the loop.
Also fullfile is recommended instead of string concatenation.
You will probably find that the files are not imported in numeric order: to get numeric order based on numbered filenames (without leading zeros, as your example shows) you will need to do either of these:
- sort the names alphanumerically.
- generate the filenames (rather than using DIR), as shown here:
Réponses (1)
"I am wonder why it happened."
Because you always load exactly the same file data (note the indexing you used):
filename{1,1}
Your code always loads the first file and ignores all the other files.
In any case your approach is not robust. Here is a simpler and more robust way to import that data:
P = 'D:\50-350\';
S = dir(fullfile(P,'*.dat'));
for k = 1:numel(S)
F = dir(fullfile(P,S(k).name));
S(k).data = readmatrix(F); % much better than EVAL and LOAD.
end
Depending on how the files are named, you might also find this useful:
Catégories
En savoir plus sur File Operations dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!