indexing error: ()-indexing must appear last in an index expression

29 vues (au cours des 30 derniers jours)
Sam
Sam le 10 Mai 2013
Commenté : Walter Roberson le 21 Déc 2016
Do you know what is wrong with my indexing below? Thanks.
vars = {'Cs' 'beta' 'As' 'TCI' 'TWI' 'hs'}
tmp = cell(size(dem)) % create 20x1 supercell
out = tmp;
tmp2 = size(vars) % create 6x1 subarrays
out2 = zeros(tmp2);
for i=1:numel(dem)
for j=1:numel(vars)
*out{i} = out2(:,:,j)(Cs{i}, beta{i}, As{i}, TCI{i}, TWI{i}, hs{i});*
end
end
Error: ()-indexing must appear last in an index expression.

Réponse acceptée

the cyclist
the cyclist le 10 Mai 2013
Modifié(e) : the cyclist le 10 Mai 2013
In MATLAB you cannot index into an array that you've already indexed into, so you cannot do this
out{i} = out2(:,:,j)(Cs{i}, beta{i}, As{i}, TCI{i}, TWI{i}, hs{i})
But assuming the rest of your code is OK (which I could not check), then you could define a temp variable
out2_tmp = out2(:,:,j);
out{i} = out2_tmp(Cs{i}, beta{i}, As{i}, TCI{i}, TWI{i}, hs{i})
  2 commentaires
Sam
Sam le 10 Mai 2013
Thanks, Cyclist. That made progress yet led to a dreaded error I've hit numerous times but don't fully understand. This is my first attempt at a nested for loop. Can you offer more help? There is no other add'l code, although FYI each 'vars' is a 20x1 cell of n x m arrays.
vars = {'Cs' 'beta' 'As' 'TCI' 'TWI' 'hs'}
tmp = cell(size(dem))
out = tmp;
tmp2 = size(vars)
out2 = zeros(tmp2);
for i=1:numel(dem)
for j=1:numel(vars)
out2_tmp = out2(:,:,j);
out{i} = out2_tmp(Cs{i}, beta{i}, As{i}, TCI{i}, TWI{i}, hs{i});
end
end
Subscript indices must either be real positive integers or logicals.
the cyclist
the cyclist le 10 Mai 2013
I can't really help debug your code, because it is not self-contained. However, I can give insight into that error.
x = [2 7 6 3];
idx_valid_integers = [1 3 4 2];
idx_valid_logical = [true true false true];
idx_invalid = [-1 0];
% Valid indexing
y = x(idx_valid_integers);
% Also valid indexing [using logical indexing]
y = x(idx_valid_logical);
% Not valid indexing (index is neither positive integer nor logical)
y = x(idx_invalid); % This will give you that same error.
The first two ways of indexing work, because I am either telling MATLAB a particular element (by its position) or by applying a logical "mask" to the entire vector.
But the third way does not work. What is the "-1" or "zeroth" element of a vector. It makes no sense.
Somehow, that is what you are doing in your code.

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Plus de réponses (1)

Bhargavkrishna Kondreddy
Bhargavkrishna Kondreddy le 26 Oct 2016
% Importing all the 300 files
files = dir( 'imageset1_*.txt'); for i=1:numel(files) A{i} = dlmread( files(i).piv, '\t', 3 , 0 ); end
% Summation of X-components of the 300 files
Xsum ='A('1)(:,3); for k = 2:299 Xsum=Xsum+A(k)(:,3); end () indexing must appear last in an index expression at
  1 commentaire
Walter Roberson
Walter Roberson le 21 Déc 2016
MATLAB does not have implicit multiplication. You need to add * as appropriate.

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