Does anyone know how to modify this program for peak load shaving using charging and discharging battery

8 vues (au cours des 30 derniers jours)
I am tryint to modify this code to shave the profile_load by energy storage battery (charging / discharging). The figure below this is my goal. Where is the orange curve is load_profile and the blue curve is charging/ discharging battery. The data in the figure below is different from the my load_profile.
Any help would be appreciated.
*********************************************************************************************************************************************************
load_profile=[250;227;206;220;197;203;210;191;353;464;518;544;588;565;562;606;576;494;409;322;301;288;268;228];
loss=0.01;
T=24;
M=1;
ESS_Cmax=90;
ESS_ch = optimvar('ESS_ch',T,'LowerBound',0,'UpperBound',M);
ESS_disch = optimvar('ESS_disch',T,'LowerBound',0,'UpperBound',M);
ESS_SOC = optimvar('ESS_SOC',T,'LowerBound',0,'UpperBound',ESS_Cmax);
Grid_E = optimvar('Grid_E',T,'LowerBound',0);
prob.Constraints.energyStorage = optimconstr(T);
prob.Constraints.energyStorage(1) = ESS_SOC(1) == 0;
prob.Constraints.energyStorage(2:T) = ESS_SOC(2:T) == ESS_SOC(1:T-1)*(1-loss) + ESS_ch(1:T-1) - ESS_disch(1:T-1);
prob.Constraints.EnergyBalance = Grid_E == load_profile - ESS_ch + ESS_disch;
%create binary variables
Z_X = optimvar('Z_X',T,'Type','integer','LowerBound',0,'UpperBound',1); % charging binary variable array
Z_Y = optimvar('Z_Y',T,'Type','integer','LowerBound',0,'UpperBound',1); % discharging binary variable array
% Consraints for binary variables
prob.Constraints.Ch_on = ESS_ch <= M*Z_X;
prob.Constraints.Dis_on = ESS_disch <= M*Z_Y;
prob.Constraints.notPositive = Z_X + Z_Y <= 1;
%**************************************************
W = optimvar('W');
Z = optimvar('Z');
prob = optimproblem;
prob.Objective = W - Z + 1/100*(sum(Z_X + Z_Y));
prob.Constraints.shaveW = W >= Grid_E;
prob.Constraints.shaveZ = Z <= Grid_E;
prob.ObjectiveSense = 'minimize';
options = optimoptions(prob.optimoptions,'Display','none')
[sol,fval,exitflag,output,lambda] = solve(prob,'Options',options)
% **************************************************
  1 commentaire
Alan Weiss
Alan Weiss le 3 Mar 2021
You set M = 1. Why? I suggest that you try 100. Or whatever your maximum value really is.
If you don't understand the code that you are using, feel free to ask what various specific lines mean. It appears to me that you are using https://www.mathworks.com/matlabcentral/answers/579006-objective-function-for-peak-shaving-and-valley-filling-of-wind-turbine-electrical-load-profile?s_tid=srchtitle .
Alan Weiss
MATLAB mathematical toolbox documentation

Connectez-vous pour commenter.

Réponses (0)

Produits


Version

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by