Please help me to plot this equation
Thanks in advance
log((1+alpha1*x/(1+alpha2*y))) -gamma*log((1+beta1*x/(1+beta2*y)));
alpha1=0.1; alpha2=0.2; beta1=0.2; beta2=1; gamma=1.3;

 Réponse acceptée

the cyclist
the cyclist le 4 Mar 2021

1 vote

Here is one way:
alpha1=0.1; alpha2=0.2; beta1=0.2; beta2=1; gamma=1.3;
x = 0 : 0.1 : 10;
y = 0 : 0.1 : 10;
[xx,yy] = meshgrid(x,y);
f = log((1+alpha1*xx./(1+alpha2*yy))) -gamma*log((1+beta1*xx./(1+beta2*yy)));
figure
surf(x,y,f)

2 commentaires

Answering the comment you placed here, then deleted.
alpha1=0.1; alpha2=0.2; beta1=0.2; beta2=1; gamma=1.3;
x = 0 : 0.1 : 10;
y = 0 : 0.1 : 10;
[xx,yy] = meshgrid(x,y);
f = zeros(size(xx));
figure
surf(x,y,f)
(I saw that you also emailed me, but I don't answer via email, so better to post here.)
Hossein Alishahi
Hossein Alishahi le 4 Mar 2021
Thank you.
But I meant
f = log((1+alpha1*xx./(1+alpha2*yy))) -gamma*log((1+beta1*xx./(1+beta2*yy)))==0
please help me in this problem

Connectez-vous pour commenter.

Plus de réponses (1)

the cyclist
the cyclist le 4 Mar 2021
Modifié(e) : the cyclist le 4 Mar 2021

0 votes

You can use the fimplicit function.
alpha1=0.1; alpha2=0.2; beta1=0.2; beta2=1; gamma=1.3;
f = @(x,y) log((1+alpha1*x./(1+alpha2*y))) -gamma*log((1+beta1*x./(1+beta2*y)));
figure
fimplicit(f,[0 100 0 10]) % Chose these plot limits after a little experimentation

2 commentaires

Hossein Alishahi
Hossein Alishahi le 6 Mar 2021
I have below code
%% Input Values
clear all
clc
alpha1=input('Enter positive "alpha1"?');
alpha2=input('Enter positive "alpha2"?');
beta1=input('Enter positive "beta1"?');
beta2=input('Enter positive "beta2"?');
lambda=input('Enter positive "lambda"?');
eta1=input('Enter positive "eta1"?');
eta2=input('Enter positive "eta2"?');
P=input('Enter positive "P"?');
%% Feasible Area
x = -1:P;m = 0; c = eta2; y = m * x + c;
plot(x, y, 'black')
y = -1:P; m = 0; c = eta1; y = m * x + c;
plot(y, x, 'black')
eta1=min (eta1,P); eta2=min (eta2,P);
if eta1==0 && eta2==0;
X=[0 0 P]; Y=[0 P 0];
fill(X,Y,[0.85 0.85 0.85]); axis([-1 P -1 P])
end
if eta1+eta2<P
X=[0 0 eta1 eta1]; Y=[0 eta2 eta2 0];
fill(X,Y,[0.85 0.85 0.85]);
else
X=[0 0 P-eta2 eta1 eta1]; Y=[0 eta2 eta2 P-eta1 0];
fill(X,Y,[0.85 0.85 0.85]); axis([-1 P -1 P])
end
X=[0 0]; Y=[0 P];
line(X,Y,'Color','black')
hold on
line(Y,X,'Color','black')
g = @(x,y) x+y-P;
y1=fimplicit(g,[0 P 0 P])
f = @(x,y) log((1+alpha1*x./(1+alpha2*y))) -lambda*log((1+beta1*x./(1+beta2*y)));
y2=fimplicit(f,[-1 P -1 P], '-')
hold on
grid on
Where I consider alpha1=1, alpha2=0.2, beta1=1; beta2=2, lambda=2, eta1=2, eta2=3, P=1
I want to find the intersection for lines in the picture. Could you please help me!
the cyclist
the cyclist le 6 Mar 2021
You might want to post a new question, so more people see this. I don't see the answer right away, and I don't think I'm going to get a chance to think about it more for a while.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Mathematics dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by