If i have a matrix of eqns, how can i sub in certain letter values now. I am using a live script where the first section creates the matrix, the second section i want to sub in the values of the constants.
%section1
close all; clear; clc;
syms A C0 Dv ka kh kt x1 x2 x3 x4 v1 v2 v3 u1 u2
%each element of the linearizes matrix
f1 = 1/A * (ka*(u1+u2)-C0*sqrt(x1-x2));
f2 = 1/A * (C0*sqrt(x1-x2)-Dv*sqrt(x2)*v1);
f3 = 1/(A*x1) * ((v2-x3)*ka*u1+(v3-x3)*ka*u2);
f4 = 1/(A*x2) * (x3-x4)*C0*sqrt(x1-x2);
AJ = jacobian([f1;f2;f3;f4],[x1 x2 x3 x4])
BJ = jacobian([f1;f2;f3;f4],[u1 u2])
BvJ = jacobian([f1;f2;f3;f4],[v1 v2 v3])
CJ = [0 kh 0 0;
0 0 0 kt]
%section 2
A = 0.785;
Dv = 2.66;
C0 = 0.056;
ka = 0.004;
kh = 2;
kt = 0.1;

 Réponse acceptée

%section1
close all; clear; clc;
syms A C0 Dv ka kh kt x1 x2 x3 x4 v1 v2 v3 u1 u2
%each element of the linearizes matrix
f1 = 1/A * (ka*(u1+u2)-C0*sqrt(x1-x2));
f2 = 1/A * (C0*sqrt(x1-x2)-Dv*sqrt(x2)*v1);
f3 = 1/(A*x1) * ((v2-x3)*ka*u1+(v3-x3)*ka*u2);
f4 = 1/(A*x2) * (x3-x4)*C0*sqrt(x1-x2);
AJ = jacobian([f1;f2;f3;f4],[x1 x2 x3 x4])
AJ = 
BJ = jacobian([f1;f2;f3;f4],[u1 u2])
BJ = 
BvJ = jacobian([f1;f2;f3;f4],[v1 v2 v3])
BvJ = 
CJ = [0 kh 0 0;
0 0 0 kt]
CJ = 
%section 2
A = 0.785;
Dv = 2.66;
C0 = 0.056;
ka = 0.004;
kh = 2;
kt = 0.1;
%section 3
subs(AJ)
ans = 
subs(BJ)
ans = 

Plus de réponses (0)

Catégories

En savoir plus sur Mathematics dans Centre d'aide et File Exchange

Produits

Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by