trying to combine cells

I have 3 cells [1x5000] , [1x3000] and [1x2000] and I want to combine these in one cell [1x10000]. With small dimensions you can try the copy paste but now this is very slow procedure.

Do you have any ideas?

Thanks in advance!

Answer 1

[Image Analyst]

Study this example:

% Original cell array, with 3 elements (cells).
ca = {ones(1,5000), rand(1,3000), zeros(1,2000)}
% Construct new cell with one element comprised of the
% contents of the other cell array's cells:
new_ca = {[ca{1}, ca{2}, ca{3}]}

Also, reading the FAQ may be helpful: http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F

[Andrei Bobrov]

new_ca = {cat(2,ca{:})};
new_ca = {[ca{:}]};

[Image Analyst]

nicolas said "Something like this,(I know that is wrong) C= [X(1, 1:5000),Y(1, 5001:8000), Z(1, 8001:10000)] Any ideas? "

Then just do this:

% Original cell array, with 3 elements (cells).
ca = {ones(1,99000), rand(1,99000), zeros(1,99000)}
% Construct new cell with one element comprised of certain specific elements 
% of the contents of the other cell array's cells:
new_ca = {[ca{1}(1:5000), ca{2}(5001:8000), ca{3}(8001:10000)]}

If you have 3 separate cells instead of a cell array, then just concatenate them and use the same solution as above.

% Three separate original cells.
ca1 = {ones(1,99000)};
ca2 = {rand(1,99000)};
ca3 = {zeros(1,99000)};
% Combine, then use same solution as above.
ca = [ca1, ca2, ca3]
% Construct new cell with one element comprised of the
% contents of the other cell array's cells:
new_ca = {[ca{1}(1:5000), ca{2}(5001:8000), ca{3}(8001:10000)]}

Answer 2

[yagnesh]

suppose x is [1x5000] , y is [1x3000] and z is [1x2000]

xyz=[x;y;z]

Answer 3

[nicolas]

I think that there is a wrong in all of these answers, the way you described helps to create a new cell array, with contents the three cells, but no in a row. I mean that I would like to have in 5000 columns the first cell, the next 3000 columns the second etc.

Something like this,(I know that is wrong) C= [X(1, 1:5000),Y(1, 5001:8000), Z(1, 8001:10000)]

Any ideas? Thanks for your help!

[Image Analyst]

It's just one line - see my comment under my answer.

Answer 4

[Andrei Bobrov]

A = {X,Y,Z};
ii = hankel([0 5000],[5000 8000 10000]);
C = arrayfun(@(x)A{x}(ii(1,x)+1:ii(2,x)),1:numel(A),'un',0);
out = {[C{:}]};

Answer 5

[nicolas]

It seems so somplicated! I don't know yet! I check this and I ll answer to you, thanks!

[Image Analyst]

Yes, cell arrays are almost always complicated. Can't you work with just normal old reliable numerical arrays? It would be so much simpler.

[nicolas]

maybe, but now I have the data in this type, its wasted time to convert them. I just need an array with all of them in a row. Nevertheless thanks again, I ll try again tmrw

Answer 6

[nicolas]

I know that it isn't so clever but finally I did it with (manual operated) "copy-paste" functions. http://www.mathworks.com/help/matlab/matlab_env/view-edit-and-copy-variables.html?searchHighlight=copy+paste+cells

Thanks for your time!