Any one can help me to check this code ?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
A = [ 1 1 5; 2 1 6; 3 7 5 ];
B = ones(3,3)
S = eye(3,3)
O = [2 7 6; 3 7 0]
for j = 1: 1: 3
R = A(1:end,j) % get 3 column vectors. therefore i will have 3 (R)'s
C = B * R ; % 3x1 vector
D = [B*S ; O,B*C]
H = [zeros(3,3); S]
end
I have doubt about the value of C, does it change with j in the loop?
by the way C is a matrix, i can not write C(j) because i want to use the whole matrix (3x3) not just some specific values inside C.
If i need to change something, please let me know.
Thanks
0 commentaires
Réponse acceptée
Azzi Abdelmalek
le 25 Mai 2013
Modifié(e) : Azzi Abdelmalek
le 25 Mai 2013
There is a small mistake, it should be O' instead of O,
A = [ 1 1 5; 2 1 6; 3 7 5 ];
B = ones(3,3)
S = eye(3,3)
O = [2 7 6; 3 7 0]
for j = 1: 3
R = A(1:end,j) % get 3 column vectors. therefore i will have 3 (R)'s
C = B * R ; % 3x1 vector
D = [B*S ; O' B*C]
H = [zeros(3,3); S]
end
3 commentaires
Azzi Abdelmalek
le 25 Mai 2013
Yes C is changing every iteration, if you need to store each value of C , you can add in the loop
C1{j}=C
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!