How can I do multiple regression (i = 1:15) in a loop?

2 vues (au cours des 30 derniers jours)
Simon
Simon le 27 Mai 2013
I got a matrix A (1x15) with each cell containing 524 x 4 of data, and a Y matrix containing 524 x1 data. I was going for :
For i = 1:15
mdl{i} = LinearModel.fit(A{1,i},Y)
end
but it didn't work
Thanks in advance!
  3 commentaires
Simon
Simon le 28 Mai 2013
It seems to work but i end up having a 1x15 matrix of mdl, but all cells are empty... it's weird
Simon
Simon le 28 Mai 2013
No error message :/

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the cyclist
the cyclist le 28 Mai 2013
This worked for me:
% Some pretend data
A = cell(1,15);
for i=1:15
A{i} = rand(524,4);
end
Y = rand(524,1);
% Do the fits
for i = 1:15
mdl{i} = LinearModel.fit(A{1,i},Y);
end
  6 commentaires
the cyclist
the cyclist le 29 Mai 2013
If the code I posted is giving completely empty results, I suggest you file a bug report.
An alternative to using LinearModel.fit is the regress() command.
Simon
Simon le 30 Mai 2013
I might report it eventually but i found out that this particular function generate an object and apparently i'm not supposed to have many objects in a single matrix. I manage to gather the Rsquared using Varname.Rsquared.Adjusted so that only answers pop out in a (1,15) matrix. The only problem i have here is that i don't have the combination variable names anymore and that might cause problem... If i try with 50 variables i won't be able to understand the answer! Thank you!!

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