Index exceeds the number of array elements (11).

This is my script.

 L_S = [37.752: L_delta_S : 83.483]';
 W_S = [12.995 : W_delta_S : 23.6205]';
 for S1 = 1:length(L_Possible_States)        
         for S2 = 1:length(W_Possible_States)
%              First part
             m = S2 + (11*S1 - 11);
             L_Possible_States(m,1) = L_S(S1);  
            
%              Second part
             W_Possible_States(m,1) = W_S(S2); 
             W_H(m,1) = -0.7469179561*W_Possible_States(m,1) + 0.0021132084*W_Possible_States(m,1)^2 + 15.62636759*W_Possible_States(m,1)^0.5 + 573.017896;
             Wdischarge(m,1) = 18775;
             Wpower(m,1) = WP(1,1)* W_H(m,1) + WP(1,2);
         end
 end

Index exceeds the number of array elements (11).

Error in Mywork (line 203)

W_Possible_States(m,1) = W_S(S2);

I have searched similar problems but still cannot handle this. Is anyone can help me? Thanks!

Answer 1

[Jan]

The message tells you, that you try to access W_S(12), but W_S has 11 elements only. This means that

W_S = [12.995 : W_delta_S : 23.6205]'

has less elements than length(W_Possible_States). The readers cannot guess, how you can handle this.

Notes:

• length is fragile, if the input is an array with multiple dimensions. It helps to avoid bugs if you use size(., dim) instead and specify the wanted dimension explicitly
• [12.995 : W_delta_S : 23.6205]' Remember that [ ] is the operator for concatenation in Matlab. a:b:c is a vector already, so it is a waste of time to concatenate it with nothing. So this is a tiny improvement: (12.995:W_delta_S:23.6205).'
• sqrt(x) is 40% faster than x^0.5 . Even if the speed is not important here, it is a good programming practize to avoid loosing time.

[Ziyi Liao]

Thank you! It works now.