solve command help needed.
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Divya Patel
le 13 Mar 2021
Commenté : Walter Roberson
le 13 Mar 2021
here is my code,only 5 lines, and i m trying to solve for b,
syms b m theta
m = 5;
theta = 20;
eq = tand(theta)==(2*(1/tand(b)))*(((m*m*(sind(b)*sind(b))-1))/(m*m*(1.4+(cosd(b)*cosd(b)))+2)) ;
solve(eq,b)
the answer i get is this ==> -(log(root(z^6 - z^4*(1238888939898706904063102115185851/2095413426666905974699416890572625 + 2864291029470578218930659559211008i/2095413426666905974699416890572625) - z^2*(2168555873514773727160036100864837/2095413426666905974699416890572625 - 2244186785976947882873506458763264i/2095413426666905974699416890572625) + (78442739762537124403601334665223/83816537066676238987976675622905 + 29528773499696682669388242878464i/83816537066676238987976675622905), z, 1))*180i)/pi
now idk where z comes from since its not part of my code, but i also saw some imaginary parts so since i wanted a real number i tried this
syms b m theta
m = 5;
theta = 20;
eq = tand(theta)==(2*(1/tand(b)))*(((m*m*(sind(b)*sind(b))-1))/(m*m*(1.4+(cosd(b)*cosd(b)))+2)) ;
solve(eq,b,'real',true)
here i get the answer
ans = (180*(2*pi*k + atan2(x, 1) - atan2(-x, 1)))/pi
now its a smaller eq but idk what the k or x values to be,and where they come from
the ideal answer should be 29.8 for b.
so any one know whats happening and how to solve this.
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Walter Roberson
le 13 Mar 2021
More solutions than you can shake a stick at.
syms b m theta
m = 5;
theta = 20;
eqn = tand(theta)==(2*(1/tand(b)))*(((m*m*(sind(b)*sind(b))-1))/(m*m*(1.4+(cosd(b)*cosd(b)))+2)) ;
sol = solve(eqn, b, 'returnconditions', true)
sol.b
sol.parameters
sol.conditions
k = 0;
z1 = solve(subs(sol.conditions, sol.parameters(1), k));
sol6_0 = simplify(subs(subs(sol.b, sol.parameters(1), k), sol.parameters(2), z1))
vpa(sol6_0)
k = 1;
z1 = solve(subs(sol.conditions, sol.parameters(1), k));
sol6_1 = simplify(subs(subs(sol.b, sol.parameters(1), k), sol.parameters(2), z1))
vpa(sol6_1)
k = -1;
z1 = solve(subs(sol.conditions, sol.parameters(1), k));
sol6_m1 = simplify(subs(subs(sol.b, sol.parameters(1), k), sol.parameters(2), z1))
vpa(sol6_m1)
2 commentaires
Walter Roberson
le 13 Mar 2021
You probably don't really care. What you probably want is more like
syms m theta
syms b
assume(b >= -90 & b <= 90)
m = 5;
theta = 20;
eq = tand(theta)==(2*(1/tand(b)))*(((m*m*(sind(b)*sind(b))-1))/(m*m*(1.4+(cosd(b)*cosd(b)))+2)) ;
vpasolve(eq, b)
all of the values in sol6_0, sol6_1, sol6_m1, and many others, are valid solutions for your equation, and you should be using them all -- unless you have physical reason to constrain the angles.
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