Problems using "datetime" cont.

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Andy Wileman
Andy Wileman le 17 Mar 2021
Commenté : Andy Wileman le 17 Mar 2021
Hi,
Having solved problems with getting the current date from a structure into a table (thank you Adam). Using "datetime" still does not seem to be carrying out the conversion. Any thoughts?
Kind regards,
Andy
table
Dates
_________________________________
"12/24/2008 9:59:47 AM.786743640"
%Current file format{'12/24/2008 9:59:47 AM.786743640'}
%Fileformat to convert to = data-20130325T004512Z.mat
date=cell2mat(dateName);
data=cell2mat(timeDom);
N = date
T = table(string(N), 'VariableNames', {'Dates'})
dt = datetime('T.Dates','Format','yyyyMMdd''T''HHmmss''Z')
% TODO: Save files
save(data, '-append', '-struct', 'dt');
Error using datetime (line 640)
Unable to convert 'T.Dates' to datetime using the format 'yyyyMMdd'T'HHmmss'Z'.
Error in extractor (line 20)
dt = datetime('T.Dates','Format','yyyyMMdd''T''HHmmss''Z')

Réponse acceptée

Stephen23
Stephen23 le 17 Mar 2021
Modifié(e) : Stephen23 le 17 Mar 2021
You should probably specify the input format to match the provided string:
S = "12/24/2008 9:59:47 AM.786743640";
D = datetime(S, 'InputFormat','MM/dd/yyyy h:m:s a.SSSSSSSSS')
D = datetime
24-Dec-2008 09:59:47
D.Format = 'yyyyMMdd''T''HHmmss''Z'''
D = datetime
20081224T095947Z
You also need to refer to the table, not define a literal character vector:
datetime( T.Dates ,...) % correct way to refert to table T.
datetime('T.Dates',...) % defines a character vector, does not help you.
  3 commentaires
Stephen23
Stephen23 le 17 Mar 2021
@Andy Wileman: note that I assumed that the trailing decimal fraction are fractional seconds. If they represent some other data, then you will need to make the required changes.
Andy Wileman
Andy Wileman le 17 Mar 2021
I think they are trailing seconds, as the data is from data aquisition. Once again, thanks.

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