# If statement for a values in a string

6 vues (au cours des 30 derniers jours)
Andre le 31 Mai 2013
Iam a Matlab newbi, so need some help. Working on a for-loop. In the for-loop my if statement doesn't work as i wish. I want it to work like this: When the value of i= one of the numbers in the string, h, make a plot of the function f(i). So the problem is the first line in the if-statement.
h=[8 17 25 30 36 41 49 58]
for i=1:65
F(i)
if i= one of the values in the string defined above
plot F(i)
end
end
Any suggestions to fix this if-statement?
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### Réponse acceptée

Jonathan Sullivan le 31 Mai 2013
The variable h does appear to be a string, but rather a vector of doubles. What you want to use to determine if a scalar is equal to any element of a vector is the function ismember
Example
ismember(i,h)
Hope this helps.
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Andre le 31 Mai 2013
Modifié(e) : Andre le 31 Mai 2013
Doesn't the ismember function only tell if its true or false?
I want my function to be plotted if i=one of the values in h. I don't want to know if i=one of the values i h or not.
Jan le 31 Mai 2013
@Andre: I do not understand the last paragraph of your comment.

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### Plus de réponses (1)

Jan le 31 Mai 2013
The most straight solution would be not to run the loop from 1 to 65, but:
h = [8 17 25 30 36 41 49 58]
for i = h
...
Now the loop runs through the elements of h only. If this does not matches your needs for any reasons, the suggested ismember is fine:
h = [8 17 25 30 36 41 49 58]
for i=1:65
F(i)
if ismember(i, h)
plot F(i)
end
end
This is leaner and faster:
if any(i == h)
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Andre le 1 Juin 2013
I understand. Thanks to both of you for helping me out:)

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