MATLAB ploting graph incorrectly, different from same code in Python.
12 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Rafael Pereira Baptista
le 18 Mar 2021
Réponse apportée : the cyclist
le 18 Mar 2021
I'm beggining to learn MATLAB.
I got the following code, but the graph doesn't match the data points when putting the P values manually.
%Pressure
P = 0:1/100:14;
%Parameters Pb
C = 0.55;
alpha = 28.9;
Ba = 0.44;
B = 43.7;
T = 300;
Vr = (1-3*C*alpha*(300-T))*(((P*Ba/B)+1).^-(1/Ba));
K = 2091*(Vr).^0.87;
Theta = 86*((Vr).^-((2.629*(Vr).^(1.2))));
%Resistivity
r = (K*T/(4*(Theta).^2))*(1-(1/18)*(Theta/T).^2+(1/480)*(Theta/T).^4);
r0 = (2091*T/(4*(86).^2))*(1-(1/18)*(86/T).^2+(1/480)*(86/T).^4);
plot(P,r/r0)

I wrote the same code for python and it ploted correctly
from pylab import plot, show, xlabel, ylabel, title
from numpy import linspace
#Pressure
P = linspace(0, 14, 100)
#Parameters Pb
C = 0.55
alpha = 28.9
Ba = 0.44
B = 43.7
T = 300
Vr = (1-3*C*alpha*(300-T))*(((P*Ba/B)+1)**-(1/Ba))
K = 2091*(Vr)**0.87
Theta = 86*((Vr)**-((2.629*(Vr)**(1.2))))
#Resistivity
r = (K*T/(4*(Theta)**2))*(1-(1/18)*(Theta/T)**2+(1/480)*(Theta/T)**4)
r0 = (2091*T/(4*(86)**2))*(1-(1/18)*(86/T)**2+(1/480)*(86/T)**4)
plot(P, r/r0)
xlabel('P(GPa)')
ylabel('R(P)/R(P0)')
title('Pb')
show()

What is wrong with my MATLAB code?
0 commentaires
Réponse acceptée
the cyclist
le 18 Mar 2021
In your definition of r, you missed a couple spots that required array operations instead of matrix operations:
%Pressure
P = 0:1/100:14;
P0 = 0.000101325;
%Parameters Pb
C = 0.55;
alpha = 28.9;
Ba = 0.44;
B = 43.7;
T = 300;
Vr = (1-3*C*alpha*(300-T))*(((P*Ba/B)+1).^-(1/Ba));
K = 2091*(Vr).^0.87;
Theta = 86*((Vr).^-((2.629*(Vr).^(1.2))));
%Resistivity
r = (K*T./(4*(Theta).^2)).*(1-(1/18).*(Theta/T).^2+(1/480).*(Theta/T).^4);
r0 = (2091*T/(4*(86).^2))*(1-(1/18)*(86/T).^2+(1/480)*(86/T).^4);
plot(P,r/r0)
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Numerical Integration and Differentiation dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
