There are two errors in my code. Can someone know how to edit it to maker it run? Thank you!
    3 vues (au cours des 30 derniers jours)
  
       Afficher commentaires plus anciens
    
    Tianlan Yang
 le 18 Mar 2021
  
    
    
    
    
    Commenté : Tianlan Yang
 le 18 Mar 2021
            
Here is the function:
function [L,U] = eluinv(A)
[~,n]=size(A);
[L,U] = lu(A);
format compact
if closetozeroroundoff(A,7) == closetozeroroundoff(L*U,7)
    disp('Yes, I have got LU factorization')
end
if closetozeroroundoff(rref(U),7) == closetozeroroundoff(rref(A),7)
    disp('U is an echelon form of A')
else
    disp('Something is wrong')
end
if rank(A) ~= min(size(A))
    sprintf('A is not invertible')
    invA=[];
    return
else
    leye = [L eye(size(L,1))];
    ueye = [U eye(size(U,1))];
    invLech = rref(leye);
    invUech = rref(ueye);
    invL = invLech(:,(n+1):size(invLech,2));
    invU = invUech(:,(n+1):size(invUech,2));
    invA = invU*invL;
    if isequal(closetozeroroundoff(invA-inv(A)),zeros(size(A)))
        disp('Yes, LU factorization works for calculating the inverses')
    else
        disp('LU factorization does not work for me?!')
    end
end
0 commentaires
Réponse acceptée
  Cris LaPierre
    
      
 le 18 Mar 2021
        The error message appears to show the reason for the error. Your matrix A must be square (3x3 or 4x4) in order to use inv.
if isequal(closetozeroroundoff(invA-inv(A)),zeros(size(A)))
                                    ^^^^^^ % Error is here
3 commentaires
  Cris LaPierre
    
      
 le 18 Mar 2021
				Your criteria do not check if the matrix is square. Perhaps you want this instead?
rank(A) ~= max(size(A))
Plus de réponses (0)
Voir également
Catégories
				En savoir plus sur Linear Algebra dans Help Center et File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

