How to improve the code for vector calculation
Afficher commentaires plus anciens
N=2;
MM=4;
AA=rand(1,12);AA1=AA(1:3);AA2=AA(4:6);AA3=AA(7:9);AA4=AA(10:12);
BB=rand(1,12);BB1=BB(1:3);BB2=BB(4:6);BB3=BB(7:9);BB4=BB(10:12);
DD=rand(1,12);DD1=DD(1:3);DD2=DD(4:6);DD3=DD(7:9);DD4=DD(10:12);
EE=rand(1,12);EE1=EE(1:3);EE2=EE(4:6);EE3=EE(7:9);EE4=EE(10:12);
HH=rand(1,12);HH1=HH(1:3);HH2=HH(4:6);HH3=HH(7:9);HH4=HH(10:12);
BBB=rand(12,3);BBB1=BBB((1:3),:);BBB2=BBB((4:6),:);BBB3=BBB((7:9),:);BBB4=BBB((10:12),:);
LAD=rand(1,4);LAD1=LAD(1);LAD2=LAD(2);LAD3=LAD(3);LAD4=LAD(4)
for iter=1:N
iter
for i=1:MM
if i==1
AA=AA1;BB=BB1;DD=DD1;EE=EE1;HH=HH1;BBB=BBB1;LAD=LAD1;
elseif i==2
AA=AA2;BB=BB2;DD=DD2;EE=EE2;HH=HH2;BBB=BBB2;LAD=LAD2;
elseif i==3
AA=AA3;BB=BB3;DD=DD3;EE=EE3;HH=HH3;BBB=BBB3;LAD=LAD3;
elseif i==4
AA=AA4;BB=BB4;DD=DD4;EE=EE4;HH=HH4;BBB=BBB4;LAD=LAD4;
end
Eeta=diag((AA+HH.*DD)./LAD)+BBB;
Delta=0.5*(1-(BB+HH.*EE)./LAD)';
Penta=Eeta\Delta;
Penta1(i,:)=Penta
end
PPP=reshape(Penta1',1,12)
end
Réponses (1)
Jan
le 6 Juin 2013
It is a bad idea to pack indices into the name of the variables like in "AA4". If you use a cell instead, the FOR-loop get's much nicer:
AA = rand(1,12);
AAC {AA(1:3), AA(4:6), AA(7:9), AA(10:12)};
...
for i = 1:MM
AA = AAC{i};
...
I do not assume that a completely vectorized version is nicer or faster.
Catégories
En savoir plus sur Variables dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!