error with sprintf add operation between 2 terms resulting in string
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Opariuc Andrei
le 25 Mar 2021
Commenté : Opariuc Andrei
le 25 Mar 2021
I used sprintf Mt1a to receive a value which someone not experienced with matlab would understand the value ,there appears to be a conflict in " Mt1a+Mt2a " which gives me multiple values ,i tried using str2double to fix my result but it returns NaN ,how can i fix the result for b ?
b=sprintf('%.0f\n',a./str2double(Mt1a+Mt2a)) % ==>how i attempted to use str2double
Mt2a=66539;
Fa=88050;
d2p=37;
p=6;
rb=0.08;
tga2p=p/(pi*d2p);
x=(tga2p+rb)/(1-(tga2p*rb));
Mt1a=sprintf('%.0f\n',Fa*(d2p/2)*x)
a=Fa*(d2p/2)*tga2p;
b=a./(Mt1a+Mt2a)
2 commentaires
Stephen23
le 25 Mar 2021
Modifié(e) : Stephen23
le 25 Mar 2021
Mt1a=sprintf('%.0f\n',Fa*(d2p/2)*x) % <- why are you converting this to character?
Mt1a+Mt2a % <- did you look at the output when you "add" two character vectors?
Mixing character vectors into your numeric operations is hindering you, not helping you. Get rid of them.
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Star Strider
le 25 Mar 2021
‘I used sprintf because that's the only command i know of ,to get from Mt1a= 2.152845579898380e+05 toMt1a=215285.’
If you want to eliminate the fractional part of the numbers, use the round, fix, floor or ceil functions, depending on the result you want. (I provided a link to round, links to the others are in that documentation.)
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Steven Lord
le 25 Mar 2021
Do you want to concatenate a number and a piece of text together?
a = '1234'; % a is a char vector
b = 5;
c = [a, num2str(b)]
as = "1234"; % as is a scalar string
b = 5;
cs = as + b % automatically converts 5 to "5" then appends it to as
Or do you want to add them?
d = a + b % add 5 to the ASCII values of the characters '1', '2', '3', and '4'
d2 = double('6789')
f = str2double(a)+b % add 5 to the number represented by a
f2 = double(as)+b % double on a string array converts it to the number it represents
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