System of linear equations with for loop

Hello, is it possible to solve a system of linear equations with a for loop? I would like to iterate one of the known parameters and see all of the solutions of the system for each iteration. Here is an example of how I am solving the system without the iteration:

A0 = 1;
B0 = 2;
C0 = 3;

syms a b c 
eqn1 = a - b == A0; 
eqn2 = a + b + c == B0;
eqn3 = a - b + c == C0; 

[A,B] = equationsToMatrix([eqn1, eqn2, eqn3], [a b c]); 
X = linsolve(A,B); 

a = double(X(1))
b = double(X(2))
c = double(X(3))

Now, what if the values of A0 are composed of a vector of 10 different values? I should have 10 values for each of the a, b, c parameters as output. I was thinking to iterate the equations with a for loop. How can I do that?

Thank you all in advance!

Answer 1

[Vishesh]

Hi @letoppina,

I understand that you want to solve a system of linear equations using a "for" loop for 10 different values of "A0" in your script.

You can achieve this using the following steps:

1. Initialize "A0" with 10 different values.
2. Initialize an empty array "final_values" to store results of all 10 iterations.
3. Use a "for" loop to iterate through all 10 values of "A0" and create a new "eqn1" equation for each value of "A0".
4. Store the result of each iteration in the "final_values" array.

The script for the above steps is provided below:

A0 = [1 2 3 4 5 6 7 8 9 10]; %taking 10 different values of A0.
B0 = 2;
C0 = 3;
 
syms a b c;
eqn2 = a + b + c == B0;
eqn3 = a - b + c == C0; 

final_values=[]; %initializing an empty array to store values of a,b and c in each iteration.

for i=1:10 % iterating each value of "A0"
eqn1 = a - b == A0(i); 
[A,B] = equationsToMatrix([eqn1, eqn2, eqn3], [a b c]); 
X = linsolve(A,B); 
final_values=[final_values;[double(X(1)) double(X(2)) double(X(3))]]; % storing values of a,b and c.
end

disp(final_values);

    0.5000   -0.5000    2.0000
    1.5000   -0.5000    1.0000
    2.5000   -0.5000         0
    3.5000   -0.5000   -1.0000
    4.5000   -0.5000   -2.0000
    5.5000   -0.5000   -3.0000
    6.5000   -0.5000   -4.0000
    7.5000   -0.5000   -5.0000
    8.5000   -0.5000   -6.0000
    9.5000   -0.5000   -7.0000

Please refer to the following documentation for more information on the "for" loop:

for loop to repeat specified number of times - MATLAB for - MathWorks India