Evaluating polynomial functions to get integer as answer

1 vue (au cours des 30 derniers jours)
Rodrigo Toledo
Rodrigo Toledo le 4 Avr 2021
I am trying to evaluate:
syms x y
eq = (x^2 + y^3 == 31)
solve(eq)
eqs = [x^2 + y^3 == 31, x^2 == 31 - y^3]
S = solve(eq,[x y])
S.x and S.y still not 2 and 3
i am expecting to get as answer two integer: x=2 and y=3. How can i do it?
Thanks

Réponse acceptée

Walter Roberson
Walter Roberson le 4 Avr 2021
Modifié(e) : Walter Roberson le 4 Avr 2021
syms x y integer
eq = (x^2 + y^3 == 31)
eq = 
solx = solve(eq,x,'returnconditions',true)
solx = struct with fields:
x: [2×1 sym] parameters: [1×0 sym] conditions: [2×1 sym]
soly = solve(solx.conditions)
soly = 
3
X = subs(solx.x,y,soly)
X = 
Y = soly
Y = 
3
Caution: this kind of process will not generally attempt to find more than one solution for solx.conditions. But you could
soly = solve(eq,y,'returnconditions',true)
soly = struct with fields:
y: [3×1 sym] parameters: [1×0 sym] conditions: [3×1 sym]
solx = arrayfun(@solve, soly.conditions, 'uniform', 0)
Warning: Unable to find explicit solution. For options, see help.
solx = 3×1 cell array
{0×1 sym} {2×1 sym} {0×1 sym}
X = solx{2}
X = 
Y = subs(soly.y(2), x, X)
Y = 

Plus de réponses (1)

darova
darova le 4 Avr 2021
solve can be used for simple problems. Use fsolve or vpasolve to get numerical results
  1 commentaire
Walter Roberson
Walter Roberson le 4 Avr 2021
Not the point. The point is that solve() is having difficulty processing integer constraints in this case. fsolve and vpasolve have no chance of processing integer constraints.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Symbolic Math Toolbox dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by