compare value between different arrays

Hi all. I have 2 array that have value. I want to compare each value of each array, but i dont know how to do that. Can somebody help me ? Thanks in advance.

[Azzi Abdelmalek]

If you have

 a=[2 3 4]
b=[1 4 0]

What should be the result of comparison?

[Lidank Abiel]

 a=[39.4029   46.6748   45.3174   26.4645   21.6932];
 b=[36.8585   47.6897   46.7784   26.9878   22.2181];

i want to compare each value of array b to array a, that the result of b approach to a. Value of array a is used here as reference.

[Iain]

By "compare", what do you mean? Do you mean:

 1. Check that each element of b is greater than, or equal to, or less than the corresponding element of a?
 2. Check that each element of b is greater than, or equal to, or less than ANY element of a?
 3. Check that each element of b is within a small error (which you haven't defined) of a (corresponding, or an element)
 4. Check that "b" is becoming more like "a"
 5. Somethign else?

[Lidank Abiel]

option 1 sir

[Iain]

 result = b > a; %(b greater than a)
 result = b >= a; %(b greater or equal to a)
 result = b == a; %(b equal to a)
 result = b <= a; %(b less than or equal to a)
 result = b < a; %(b less than a)

result is the same length as b, and is 1 (true) when b is that comparison to a, and 0 (false) everywhere else.

 all(result) will be 1 (true) if all the elements of b are "that comparison"
any(result) will be 1 (true) if any of the elements of b are "that comparison"

 result = b > (5*a); %(b greater than five times a)

[Lidank Abiel]

yes, check each element of b less than or equal to a. ( I mean, check b[1] to a[1], b[2] to a[2], etc. If the result are as expected, it will be 1 (true).

Answer 1

[Azzi Abdelmalek]

a=[2 3 4]
b=[1 4 0]
comp=a<b

[Lidank Abiel]

 a=[39.4029   46.6748   45.3174   26.4645   21.6932];
 b=[36.8585   47.6897   46.7784   26.9878   22.2181];

i want to compare each value of array b to array a, that the result of b approach to a. Value of array a is used here as reference.

[Azzi Abdelmalek]

Ok, but what should be the result in this case?

[Lidank Abiel]

I had the training data, which is a. later, I enter test data, namely b. The b value would I compare it with a. if the value of b close to the value of a, then the data is valid. that's what I want to do. is there a way to make it?

[Tom]

How do you define close?

 a=[39.4029   46.6748   45.3174   26.4645   21.6932];
 b=[36.8585   47.6897   46.7784   26.9878   22.2181];

 tol = 1;

 %check that the elements of a and b are within a given tolerance
 abs(a-b) <= tol

[Lidank Abiel]

ya, like that, but each value from an array sir, not overall ( i mean not (a-b), but maybe like (a1-b1). is it possible ?.

[Azzi Abdelmalek]

Do you want to compare the first value of a with the first of b, and so on? To be more clear, please post what should be the result for your example!

[Lidank Abiel]

 function deteksi_Callback(hObject, eventdata, handles)
% hObject    handle to deteksi (see GCBO)
% eventdata  reserved - to be defined in a future version of MATLAB
% handles    structure with handles and user data (see GUIDATA)
 global capture

 cla(handles.axes3);
 cla(handles.axes7);
 set(handles.status, 'String', '------');
 set(handles.nominal, 'String', '------');
 set(handles.euc_uji, 'String', '------');
 set(handles.euc_sampel, 'String', '------');
 toleran=0;

 if(isempty(get(handles.toleransi,'String')))
    toleran=93;
else
    toleran=eval(get(handles.toleransi,'String'));
end

 load dataeuc;
 [x y]=size(nilaieuc);
 jum=0;
 citragray=rgb2gray(capture);
 citrafilter=medfilt2(citragray,[3 3]);
 citraedge=edge(citrafilter,'canny',[0.01 0.11]);
 jlh=20;
 citraedgethin=bwmorph(citraedge,'thin',jlh);
 citraakhir=imcomplement(citraedgethin);

 [ximg2 yimg2]=size(citraakhir);
jum=0;
for i=1:ximg2
   for j=1:yimg2
      if(citraakhir(i,j)==0)
          jum=jum+1;
         pos(jum,1)=i;
         pos(jum,2)=j;
      end
   end
end
[ximg3 yimg3]=size(pos);
euclid1=0;
for i=1:ximg3-1
   euc(i)= sqrt(((pos(i,1)-pos(i+1,1))^2)+((pos(i,2)-pos(i+1,2))^2));
   euclid1=euclid1+euc(i);
end
axes(handles.axes3);
imshow(citraakhir);
euclid1
set(handles.euc_uji,'String',euclid1); %set nilai euclidean gambar di static text

 bandingkan=0;

 for counti=2:x  
    counti 
    euclid2=nilaieuc(counti) 

    besar=0;
    kecil=0;
    temp_bandingkan=0;

    if(euclid1>=euclid2)
        besar=euclid1;
        kecil=euclid2;
    else
        besar=euclid2;
        kecil=euclid1;
    end      
    temp_bandingkan=(kecil/besar)*100

    if(temp_bandingkan>toleran)        
    %set(handles.euc_uji,'String',toleran);
    if(temp_bandingkan>bandingkan)
        bandingkan=temp_bandingkan;
        posisikoin=counti;      
    end

    end   

 end

This is it sir. I want to make like this.

[Azzi Abdelmalek]

I've asked a simple question: what should be the result for the short example you gave.

[Lidank Abiel]

to save the largest value and it is used as a reference in the percentage of proximity or similarity.

the 'toleran = 93' seems like minimal percentage tolerance. and the 'temp_bandingkan=(kecil/besar)*100' is to know the percentage.

[Jan]

The code does not really answer the question, so I ask again: What is the desired result for the values:

a = [39.4029   46.6748   45.3174   26.4645   21.6932];
b = [36.8585   47.6897   46.7784   26.9878   22.2181];

[Lidank Abiel]

I want that values used to percentage of proximity.

My plan, i set value for tolerance, example, tolerance = 93. Then, i process image to get the euclidean value. The result above, is value from 2 image. and then, i want to calculate 2 value above ( maybe divided ) if the result approach to value tolerance, so, the image have percentage minimal similarity 90%.

I'm sorry make all of you confused. I'm new in programming. So, I explained it according to my knowledge.

Thanks in advance.

[Jan]

Thanks for the explanantions. Unfortuantely I do not understand this:

 i want to calculate 2 value above ( maybe divided ) if the result approach to value tolerance, so, the image have percentage minimal similarity 90%.

I still do not know hwta kind of result you expect for the above mentioned input data. Are you able to calculate it manually or give a definition of the calculations? In the comments to the question you wrote "i want to compare each value of array b to array a". As soon as it is explained, what "campare" means explicitly, I assume the problem can be solved in seconds. So please try to explain this clearly.

Answer 2

[Thorsten]

You can compute two fractions a/b and b/a, and then take the minimum to ensure that the value is not above 100%. Then take the minimum of these values to get "percentage minimal similarity"

min_similarity = min(min([a./b; b./a]))