Matlab don't show calculated variables.

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Tiago Araujo
Tiago Araujo le 13 Avr 2021
I wrote this:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
R=solve([f0,f1],[C0,C1]);
C0 = R.C0;
C1 = R.C1;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f2,f3],[C2,C3]);
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
disp (Y(X));
FLECHA = Y(L/2)
But Matlab returns:
C =
0
- C3*L^2 - C2*L
(P*(EI1*L + 11*EI2*L))/(4*(EI1^2 + 14*EI1*EI2 + EI2^2))
-(P*(EI1 + 7*EI2))/(6*(EI1^2 + 14*EI1*EI2 + EI2^2))
______________________________________________
Y(X)
C3*X^3 + C2*X^2 + C1*X + C0
FLECHA
(C3*L^3)/8 + (C2*L^2)/4 + (C1*L)/2 + C0
It dont show Y(X) in terms of calculated values of C0, C1, C2 and C3.
I Want the Y(x) in function of P, L, EI1, EI2, (...), with this script these variables C0, C1... are calculateds but MATLAB dont write Y(X) em terms of them.

Réponse acceptée

Tiago Araujo
Tiago Araujo le 14 Avr 2021
Modifié(e) : Walter Roberson le 14 Avr 2021
I fixed doing:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f0,f1,f2,f3],[C0,C1,C2,C3]);
C0=S.C0;
C1=S.C1;
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
disp (Y(X));
FLECHA = Y(L/2)

Plus de réponses (1)

Jan
Jan le 14 Avr 2021
I get a dfifferent output than you:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
R=solve([f0,f1],[C0,C1]);
C0 = R.C0;
C1 = R.C1;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f2,f3],[C2,C3]);
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
Y(X)
disp (Y(X));
FLECHA = Y(L/2)
FLECHA = 
  1 commentaire
Tiago Araujo
Tiago Araujo le 14 Avr 2021
Hi! Thanks!
But, have you seen that the C3 and C2 are still present in the Y(X) instead of their value in function of EI, P and L... ?
I need Y(X) only in function of EI1 EI2 P and L...

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