Effacer les filtres
Effacer les filtres

error in resultes of "OR" operator

1 vue (au cours des 30 derniers jours)
Aseel H
Aseel H le 29 Juin 2013
in the following code I need subtract the values 255 and 254 by 1
and adding the value 0 and 1 by 1 and the other values don't change
X=[255 250 0 100 38 47 150 254
253 251 250 0 0 47 25 252
0 0 0 90 145 74 30 249
200 220 0 1 2 3 225 4
0 255 251 0 4 20 35 245
255 250 0 100 38 47 150 254
200 220 0 1 2 3 225 4
253 251 250 0 0 47 25 252];
Max = 255;
Min = 0;
[x,y] = size(X);
for i= 1:x
for j = 1:y
if X(i,j)==(Max | Max-1)
X1(i,j) = X(i,j)-1;
elseif X(i,j)== (Min | Min+1)
X1(i,j) = X(i,j)+1;
else
X1(i,j)= X(i,j);
end
end
end
**************************************
but resultes not change:it give me
X1=[255 250 0 100 38 47 150 254
253 251 250 0 0 47 25 252
0 0 0 90 145 74 30 249
200 220 0 1 2 3 225 4
0 255 251 0 4 20 35 245
255 250 0 100 38 47 150 254
200 220 0 1 2 3 225 4
253 251 250 0 0 47 25 252];
Please....I need know what error in the code

Réponse acceptée

the cyclist
the cyclist le 29 Juin 2013
You have a syntax problem when you try to do
X(i,j)==(Max | Max-1)
because that is not going to check whether X(i,j) is in a set. That is valid MATLAB syntax, but it is not doing what you think it is. You might want to read the documentation for the or() function to see exactly what it does:
doc or
Instead, I think you want the syntax
if (X(i,j)==Max) | (X(i,j)==(Max-1))
You could also use
if ismember(X(i,j),[Max Max-1])
Finally, note that you can do this operation on the entire matrix at once:
X1 = X;
idxHi = ismember(X,[255,254])
X1(idxHi) = X(idxHi)-1;
idxLo = ismember(X,[0,1])
X1(idxLo) = X(idxLo)+1;

Plus de réponses (1)

Walter Roberson
Walter Roberson le 29 Juin 2013
X(i,j)== (Min | Min+1)
means to evaluate the logical condition (Min | Min+1) and then compare that logical result to what is in X(i,j).
Try
if X(i,j) == Min | X(i,j) == Min+1

Catégories

En savoir plus sur Multidimensional Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by