fsolve does not work anymore

I tried to use fsolve in Matlab2013a, but it doesn't work anymore. Is is changed to fzero?
Here is my code:
x(:,1)=table(:,1);
x(:,2)=table(:,2)*10/60*2*pi;
x(:,3)=table(:,3)/100;
F=@(c)x(:,1).*x(:,2)./(c(1)*(x(:,1)/(3/2*1/2*c(2))).^2+x(:,2).*x(:,1)/(3/2*1/2))-x(:,3);
c0=[0.5,2];
options=optimset('Display','iter');
c1=fzero(F,c0,options);
But there is an error:
Error using fzero (line 233)
FZERO cannot continue because user supplied function_handle ==>
@(c)x(:,1).*x(:,2)./(c(1)*(x(:,1)/(3/2*1/2*c(2))).^2+x(:,2).*x(:,1)/(3/2*1/2))-x(:,3)
failed with
the error below.
Attempted to access c(2); index out of bounds because numel(c)=1.
Error in twtable (line 82)
c1=fzero(F,c0,options);
What's going on here?
Thank you very much for your help!
Fan

 Réponse acceptée

Matt J
Matt J le 30 Juin 2013
Modifié(e) : Matt J le 30 Juin 2013

0 votes

If you no longer have the Optimization Toolbox, you can probably get away with FMINSEARCH instead, since it is only a 2-parameter problem
c1 = fminsearch(@(c) norm(F(c)) , c0)

Plus de réponses (1)

Walter Roberson
Walter Roberson le 30 Juin 2013

1 vote

fsolve() was not changed to fzero(). fzero() is a different routine that takes different arguments than fsolve() does.
fsolve() is part of the Optimization Toolbox, which you perhaps have not installed or not licensed for your R2013a system.

Catégories

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by