Remove text in a string with numbers

How can I remove the text part and obtain a vector of just the last numbers?

e.g

Model1__DK1_5450.0

Model2__DK2_6969.0

Model3__DK3_3398.0

Answer 1

[Image Analyst]

You need to use digitsPattern:

txt = 'Model1__DK1_5450.0 '
pat = digitsPattern;
onlyNumbers = extract(txt, pat)

onlyNumbers =

4×1 cell array

{'1' }

{'1' }

{'5450'}

{'0' }

or you can use logical indexing:

digitIndexes = txt >= '0' & txt <= '9';
onlyNumbers = txt(digitIndexes)

onlyNumbers =

'1154500'

Or you can do fancier parsing if you just want certain numbers. Such as:

setOf4Digits = onlyNumbers(3:end-1); % Get only the 5450

Do you want the underlines, dots, and minus signs included?

[Chiara Scarpellini]

i would like the vector to be like this:

5450.0

6969.0

3398.0

-777.0

Is there a way to tell Matlab to remove everything before the number or the minus sign in case there's one?

[Image Analyst]

Well, you can either use indexing like this:

txt = 'Model1__DK1_5450.0 '
lastUnderlineIndex = find(txt == '_', 1, 'last');
% Extract from one past the last underline onwards.
onlyNumbers = strtrim(txt(lastUnderlineIndex + 1: end)) % strtrim gets rid of trailing space.

or you can use the regexp() method like Star shows. Your choice - either works.

In your original post, you posted strings with a trailing space. If you don't have that, you can omit the call to strtrim().

[Image Analyst]

@Chiara Scarpellini, just checking back. You did not accept either answer. Are you still there?