Finding the index of duplicate rows in a cell

I have A and B

A = [3,8; 8,9; 8,9; 3,9; 3,9; 3,5; 5,10; 5,10; 3,10; 3,17; 3,17; 11,17; 10,11; 10,11; 3,10];
B = {[3,8;8,9;9,3];[3,5;5,10;3,10];[3,17;3,10;10,11;11,17]};

I want to find indices of all rows in the cell and the repeated rows

I use this code

for i=1:numel(B)
    [~,X] = intersect(A,sort(B{i},2),'rows','stable');
    index_temp{i} = X;
end

But it does not give me for the repeated rows

Result should be:

index_temp ={[1;2;3;4;5],[6,7,8,9],[10,11,15,13,14,12]}

Answer 1

[Jan]

A = [3,8; 8,9; 8,9; 3,9; 3,9; 3,5; 5,10; 5,10; 3,10; 3,17; 3,17; 11,17; 10,11; 10,11; 3,10];
B = {[3,8;8,9;9,3]; [3,5;5,10;3,10]; [3,17;3,10;10,11;11,17]};

result = cell(1, numel(B));   % Pre-allocate
for k = 1:numel(B)
    X = ismember(A, sort(B{k}, 2), 'rows');
    result{k} = find(X);
end