Effacer les filtres
Effacer les filtres

How to open file array with fopen?

13 vues (au cours des 30 derniers jours)
Jacky
Jacky le 1 Juil 2013
Hi, I have a list of files that look like this:
J={'File1', 'File2', 'File3'}
It is not possible to open the file using fopen this way:
for i=1:length(J)
fid=fopen('J(1)', 'r')
%Some algorithms here...
fclose(fid)
end
Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!

Réponse acceptée

Jonathan Sullivan
Jonathan Sullivan le 1 Juil 2013
You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.
Try replacing your fopen line with this
fid = fopen(J{i},'r');
  1 commentaire
Jacky
Jacky le 1 Juil 2013
It works. I thought I did that and it it didn't work. It must be something that I missed earlier on. Thank you so much for pointing that out for me.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 1 Juil 2013

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