How to open file array with fopen?

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Hi, I have a list of files that look like this:
J={'File1', 'File2', 'File3'}
It is not possible to open the file using fopen this way:
for i=1:length(J)
fid=fopen('J(1)', 'r')
%Some algorithms here...
fclose(fid)
end
Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!

Accepted Answer

Jonathan Sullivan
Jonathan Sullivan on 1 Jul 2013
You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.
Try replacing your fopen line with this
fid = fopen(J{i},'r');
  1 Comment
Jacky
Jacky on 1 Jul 2013
It works. I thought I did that and it it didn't work. It must be something that I missed earlier on. Thank you so much for pointing that out for me.

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More Answers (1)

Walter Roberson
Walter Roberson on 1 Jul 2013

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