How do I solve this error?
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Axelina Lindgren
le 25 Avr 2021
Commenté : Axelina Lindgren
le 25 Avr 2021
My teacher put in (from what I can tell) an identical code but I can't get it working. Can somebody help me make it work and explain the error?
n1 = 1; %utanför linsen
n2 = 1.5; %i linsen
D = 10; %linsens diameter (cm)
R = D./2; %linsens radie (cm)
d = 10; %fokallängd (cm)
lopt = n1*sqrt(d.^2 + R.^2); %Optiska vägen då strålen inte bryts i linsen
Y = linspace(0, R, 1000);
X = linspace(0, d, 1000);
for ii = 1:length(Y)
L1(:,ii) = sqrt( (d-X).^2 + Y(ii).^2)*n1;
L2(:,ii) = X*n2;
LoptTemp(:,ii) = L1(:,ii) + L2(:,ii);
diff(:,ii) = abs(LoptTemp(:,ii) - lopt);
[difference minIndex(ii)] = min(diff(:,ii));
x_fit(ii) = X(minIndex(ii));
end
figure
plot(x_fit, Y, 'black');
hold on
plot(x_fit.*-1, Y, 'black');
hold on
plot(x_fit, -Y, 'black');
hold on
plot(x_fit.*-1, -Y, 'black');
hold on
ylim([-max(Y)-3, max(Y)+3]);
The error message is:
Conversion to function_handle from double is not possible.
Error in OptikVaglaraUppgift2 (line 75)
LoptTemp(:,ii) = L1(:,ii) + L2(:,ii);
Grateful for help!
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Réponse acceptée
Jan
le 25 Avr 2021
The error message means, that the variable LoptTemp has been defined as function handle before.
A pre-allocation solves the problem:
LoptTemp = zeros(length(Y), length(Y));
If you insert this code in a function, the workspace is clean and formerly defined variables to not influence the stability.
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