Effacer les filtres
Effacer les filtres

How to change x-axis values from iteration to time?

3 vues (au cours des 30 derniers jours)
Khan
Khan le 26 Avr 2021
Commenté : Khan le 26 Avr 2021
Hello,
I have a simple problem. I have generated a matrix called "A" (2000 by 1970). The rows of the matrix are velocity vectors while the columns represents the iteration numbers. In other words, the row vectors values are changing with iteration. A simple plot is given in the picture.
let's plot row number 277 of the given matrix,
figure (1)
plot(1:1970, A(277,:))
Now I would like to plot the same row vectors against the time (time on x-axis). The intial time is zero, final time should be 1.970 with time interval 0.001.
Can someone recomend how can I do it. Thank you.

Réponse acceptée

Walter Roberson
Walter Roberson le 26 Avr 2021
dt = 0.001;
time = (0:size(A,2)-1) * dt;
plot(time, A(277,:));
Note that the final value will be 1.969 not 1.970 since your time starts at 0.
  3 commentaires
Walter Roberson
Walter Roberson le 26 Avr 2021
To get exactly 1.970 with dt 0.001 and starting from 0, you would need your A to have 1971 columns instead of 1970.
Khan
Khan le 26 Avr 2021
Ok, Thank you.

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