Check if all values in cell array are 'on'
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I created an array of objects in app designer. They're all images.
images=[app.Image1,app.Image2,.......,app.ImageX];
now I get their visible property
check=get(images,'Visible');
that gives me a cell array of 'on' and 'off' values. I want to check if all the values in the array are 'on'. How do I do that? I tried combining it into a matrix, but got errors.
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Image Analyst
le 26 Avr 2021
Try this:
>> ca = {'on', 'on', 'on'}
ca =
1×3 cell array
{'on'} {'on'} {'on'}
>> allOn = all(ismember(ca, {'on'}))
allOn =
logical
1
>> ca = {'on', 'on', 'off'}
ca =
1×3 cell array
{'on'} {'on'} {'off'}
>> allOn = all(ismember(ca, {'on'}))
allOn =
logical
0
3 commentaires
Vojtech Siler
le 26 Avr 2021
Image Analyst
le 27 Avr 2021
You changed something. My code works. I don't have 34 lines in my code. I had only 2 lines and they worked. You don't need anonymous functions, strcmp(), cellfun(), etc. All you need is the single line of code I gave you that calls ismember().
Vojtech Siler
le 27 Avr 2021
One easy way to do this is to use a string.
A = {'on', 'on', 'on'};
all(A == "on")
2 commentaires
Vojtech Siler
le 26 Avr 2021
DGM
le 27 Avr 2021
It depends what version you have. This usage with the double quoted string needs R2016b to work (IIRC). At least it doesn't work for me in R2015b.
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