Help with the surf function

I am trying to create a surface plot of a matrix I created, but I need to make lattitude and longitue in to 180x360 matrices as well in order for the function to work. My code is below:

%Plot Slopematrix
addpath('C:\Users\Falon Treis\Documents\MATLAB\CE1_2C_slopematrix.mat');
%addpath('C:\Users\Falon Treis\Documents\MATLAB\CE2_2C_slopematrix.mat');
load('CE1_2C_slopematrix.mat')

k = 1:180; %lat make have 180x 360 matrix
m = 1:360; %long
z = slopematrix; %180x360

surf(k, m, z)
%surf(k, m, z)

save CE1_2C_slope_plot.mat
%save CE2_2C_slope_plot.mat

Answer 1

[Walter Roberson]

surf(k, m, z.')

Remember that the rows correspond to y not to x

[Falon Treis]

I am not sure how that helps me change the fact that the lattitude matrix has 180 and the longitude matrix has 360

[Walter Roberson]

A demonstration that transposing z does work:

k = 1:180; %lat make have 180x 360 matrix
m = 1:360; %long

slopematrix = sort(rand(length(k), length(m)));
size(slopematrix)

ans = 1×2

180 360

z = slopematrix;

try
surf(k, m, z)
disp("(k,m,z) succeeded!");
catch ME
disp("(k,m,z) failed!");
end

(k,m,z) failed!

try
surf(k, m, z.')
disp("(k,m,z.') succeeded!");
catch ME
disp("(k,m,z.') failed!");
end

(k,m,z.') succeeded!

[Falon Treis]

I don't understand why you are saying to transpose z when I am trying to transpose k and m to fit z. What exactly does transposing z do and won't I be messing with the placement of the values in the slope matrix?

[Walter Roberson]

lat is vertical, not horizontal, so you should not be using it as your x.

k = 1:180; %lat make have 180x 360 matrix
m = 1:360; %long
slopematrix = sort(rand(length(k), length(m)));
size(slopematrix)

ans = 1×2

180 360

z = slopematrix;

surf(m, k, z)
xlabel('long')
ylabel('lat')
zlabel('slope')

[Falon Treis]

Ok. I see that now. Thank you very much for your time and patience.