Effacer les filtres
Effacer les filtres

Conversion to cell from char is not possible.??

14 vues (au cours des 30 derniers jours)
Hind Haboubi
Hind Haboubi le 30 Avr 2021
Commenté : Hind Haboubi le 30 Avr 2021
Hello guys, this is my code:
inp = input('Enter file :');
v = VideoReader(inp);
myVideo = VideoWriter('TESTVID.mp4');
myVide.Quality = 50;
muVideo.FrameRate = 15;
k=0;
outclass = [];
outclass1 = [];
for i=1:1:200
str=int2str(i);
i;
videoFrame = read(v,i);
I = videoFrame;
I = imresize(I,[224 224]);
%[bboxes,scores,label] = detect(detector,I);
all = [];
lab = [];
kk=0;
if isempty(bboxes)
bboxes = [1 1 1 1];
lab = ['none'];
end
for ii=1: size(bboxes,1)
kk=kk+1;
cr = imcrop(I,bboxes(ii,:));
cr = imresize(cr,[224 224]);
out = classify(convnet,cr);
if out=='VEHICULE ENDOMMAGER';
aaaa='VEHICULE ENDOMMAGER';
predict=1
lab=[lab ; (aaaa)];
elseif out=='VEHICULE NONENDOMMAGER';
aaaa='VEHICULE NON ENDOMMAGER';
predict=2
lab=[lab ; (aaaa)];
else
lab=[lab ; 'none'];
predict=3
end
outclass=[outclass ; predict ];
outclass1=[outclass1 , lab ];
end
label_str = cell(size(lab,1),1);
conf_val = lab;
for iii=1:size(lab,1)
label_str(iii) = conf_val(iii);
end
end
And i'm getting this error what should I do please:
Conversion to cell from char is not possible.
Error in NOUVEAU (line 166)
label_str(iii) = conf_val(iii);

Réponse acceptée

Walter Roberson
Walter Roberson le 30 Avr 2021
label_str{iii} = conf_val(iii);

Plus de réponses (0)

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